Question

此代码为i和＆i打印不同的值，并且它们都不等于10。请解释一下这两个数字所表示的含义。

#include<stdio.h>
int main(){
    int p=10;
    int *i=&p;
    printf("%d %d",i,&i);
}

This is what the output look like

Answer 1

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Answer 2

这是代码的修改版本，在printfs中带有注释。请注意，我添加了第三个printf来引用int

中的p

#include<stdio.h>
int main(){
    int p=10;
    int *i=&p;
    printf("'i'  = %p is the address of the int stored in variable p\n",(void *)i);
    printf("'&i' = %p is the address of the pointer to an int called i\n",(void *)&i);
    printf("'*i' = %d is the int that is stored at the location in i which points to p\n",*i);
}

'i' = 0x7ffee4e63abc is the address of the int stored in variable p
'&i' = 0x7ffee4e63ab0 is the address of the pointer to an int called i
'*i' = 10 is the int that is stored at the location in i which points to p

指针与指针位置之间的差异

2 个答案: