我正在尝试使用 pybind11 库从称为 env_tensorflow 的python环境中执行python解释器。
尽管如此,即使我将cpp文件包含并链接到该环境( env_tensorflow )中包含的pybind11库中,解释器也会将其二进制路径打印为:
/ usr / bin / python3
但是,我希望输出为:
/ home / user / miniconda3 / envs / env_tensorflow / bin / python3
我在做什么错?如何在特定环境中运行python解释器?
main.cpp
#include "/home/user/miniconda3/envs/env_tensorflow/include/python3.6m/Python.h"
#include "/home/user/miniconda3/envs/env_tensorflow/include/python3.6m/pybind11/pybind11.h"
#include "/home/user/miniconda3/envs/env_tensorflow/include/python3.6m/pybind11/embed.h"
namespace py = pybind11;
int main() {
py::scoped_interpreter guard{};
py::module sys = py::module::import("sys");
py::print(sys.attr("executable"));
//prints: /usr/bin/python3
//expected print: /home/user/miniconda3/envs/env_tensorflow/bin/python3
return 0;
}
CMakeLists.txt
cmake_minimum_required(VERSION 3.12)
project(my_proj)
set(CMAKE_CXX_STANDARD 11)
add_library(my_python3.6m SHARED IMPORTED)
set_target_properties(my_python3.6m PROPERTIES
IMPORTED_LOCATION "/home/user/miniconda3/envs/env_tensorflow/lib/libpython3.6m.so"
INTERFACE_INCLUDE_DIRECTORIES "/home/user/miniconda3/envs/env_tensorflow/include/python3.6m/"
)
add_executable(my_proj main.cpp)
target_link_libraries(my_proj my_python3.6m)
答案 0 :(得分:1)
您需要激活Conda环境:
source activate env_tensorflow
完成此操作后,您应该能够使用正确的Python解释器运行cmake,make和您的应用程序。您可能不需要CMake中的IMPORTED目标,只要在构建过程中环境处于活动状态,就可以照常链接到python3.6m
。