Question

我有一系列的收藏品。在收藏中我有关系。在这些关系中如何使用whereIn？

$arrayCollections = $category->products;

$arrayCollections = $arrayCollections->character->whereIn('id', [1,2,3,4]); //I need use whereIn in character relation. I get error: Property [character] does not exist on this collection instance.

foreach($arrayCollections as $product) {
    .... //but in foreach I can use $product->character
}

产品型号中的关系：

public function character()
{
    return $this->hasMany('App\Models\ProductCharacter');
}

Answer 1

尝试一下：

$characters = $category->products()->character()->whereIn('id', [1,2,3,4])->get();

foreach($characters as $character) {
    // $character
}

Answer 2

您似乎需要间接关系。最好的方法是使用hasManyThrough

在您的Category模型中

public function characters() {
     return $this->hasManyThrough(Character::class, Product::class); // Has many characters through products
}

然后您可以直接执行以下操作：

 $characters = $category->characters()->whereIn('id', [ 1, 2, 3, 4 ])->get();

Answer 3

这是什么？我添加了first（）：

$characters = $category->products()->first()->character()->whereIn('id', [1,2,3,4])->get();

foreach($characters as $character) {
    // $character
}

Answer 4

您可以尝试

$arrayCollections = $category->products()->with('character')->whereIn('id' ,  [1,2,3,4])->get();

foreach($arrayCollections as $product) {}

Answer 5

您应该使用whereHas（）方法和with（）方法。

$arrayCollections = $category->products()
    ->whereHas('character', function($character){
        $character->whereIn('id' ,  [1,2,3,4]);
    })
    ->with('character')->get();

这将为您提供一系列附加有“字符”且ID为[1,2,3,4]的“产品”。

Laravel whereIn在数组中

5 个答案: