我有一个宏,该宏试图从页面中提取所有href值,但似乎只获得第一个。如果有人可以帮助我,将不胜感激。
我使用的网址是https://www.facebook.com/marketplace/vancouver/entertainment
<div class="_3-98" data-testid="marketplace_home_feed">
<div>
<div>
<div class="_65db">
<a class="_1oem" href="/marketplace/item/920841554781924" data-testid="marketplace_feed_item">
<a class="_1oem" href="/marketplace/item/580124349088759" data-testid="marketplace_feed_item">
<a class="_1oem" href="/marketplace/item/1060730340772072" data-testid="marketplace_feed_item">
Sub Macro1()
``marker = 0
Set objShell = CreateObject("Shell.Application")
IE_count = objShell.Windows.Count
For x = 0 To (IE_count - 1)
On Error Resume Next ' sometimes more web pages are counted than are open
my_url = objShell.Windows(x).document.Location
my_title = objShell.Windows(x).document.Title
If my_title Like "Facebook" & "*" Then 'compare to find if the desired web page is already open
Set ie = objShell.Windows(x)
marker = 1
Exit For
Else
End If
Next
Set my_data = ie.document.getElementsByClassName("_3-98")
Dim link
i = 1
For Each elem In my_data
Set link = elem.getElementsByTagName("a")(0)
i = i + 1
'copy the data to the excel sheet
ActiveSheet.Cells(i, 4).Value = link.href
Next
End Sub
答案 0 :(得分:2)
您可以使用CSS选择器组合来获取元素。如果您提供实际的HTML,而不是提供图像,则将更易于测试和确定最佳组合。通过AppComponent
方法应用选择器,以返回所有匹配元素的<router-outlet [routes]="Routes.all"></router-outlet>
。您遍历/products/add
的{{1}},以按从querySelectorAll
到nodeList
的索引访问项目。
VBA:
.Length
css选择器组合为nodeList
,它选择具有0
类的元素的.Length-1
属性。 Dim aNodeList As Object, i As Long
Set aNodeList = ie.document.querySelectorAll("._1oem[href]")
For i = 0 To aNodeList.Length-1
Activesheet.Cells(i + 2,4) = aNodeList.item(i)
Next
是类选择器,._1oem[href]
是属性选择器。这是一种fast且健壮的方法。
以上假设没有父href
标签可以协商。
与这两个属性(而不是类)匹配的替代选择器将是:
_1oem
完整示例:
"."
答案 1 :(得分:1)
您只需要在每个具有_3-98类的元素中请求第一个锚点元素。遍历父元素内锚元素的集合。
...
dim j as long
Set my_data = ie.document.getElementsByClassName("_65db")
For Each elem In my_data
for i = 0 to elem.getelementsbytagname("a").count -1
j = j+1
ActiveSheet.Cells(j, 4).Value = elem.getElementsByTagName("a")(i).href
next i
Next elem
...