使用rethinkDB显示一周中每一天的数据 r.row('time_create')。dayOfWeek()
[
{
detail: "no",
order_id: "03",
status: "Delivery",
time_create: "2018-09-23T11:06:30.164Z",
time_success: "2018-09-23T11:06:30.164Z"
}
]
要这样
{
"date":
{
"Sun": [
{
"order_id": "00004568",
"status": "Delivery",
"time_create": "09/16/2018 10:09:39",
"time_success": "09/19/2018 10:39:40",
"detail": ""
}
],
"Mon": [
{
"order_id": "00004568",
"status": "Delivery",
"time_create": "09/17/2018 10:09:39",
"time_success": "09/19/2018 10:39:40",
"detail": ""
},
]
}
}
我不知道如何解决它或将其原样写出
答案 0 :(得分:1)
您可以将group与键名,索引,ReQL或自定义函数一起使用。在您的情况下,应该这样做:
r.db('db').table('table')
.getAll(...)
.filter(...)
.group(
r.row('time_create').dayOfWeek()
)
然后,在您的回调中,您可以轻松地将此结果转换为所需的结构。