Question

表

| patientFirstName | patientMiddleName | patientLastName |  startdate |    enddate |    
|------------------|-------------------|-----------------|------------|------------|    
|          Patient |              Demo |            Test | 2018-09-02 | 2018-09-08 |    
|             John |               Doe |            Demo | 2018-09-02 | 2018-09-14 |    
|         Demo User|                   |                 | 2018-09-18 | 2018-09-28 |

在上表中，我尝试搜索用户“ Demo User”，搜索输入为“ demouser”。我尝试修剪空白，但仍然看不到结果。

DECLARE @searchInput varchar(10)
DECLARE @startTime DATE
DECLARE @endTime DATE
SET @searchInput = 'demouser'
SET @startTime   = '2018-09-18'
SET @endTime     = '2018-09-28'

SELECT * FROM PatientDemoTable
WHERE (@startTime IS NULL OR startdate >= @startTime)
AND   (@endTime   IS NULL OR enddate   <= @endTime)
AND   ( LTRIM(RTRIM(@searchInput)) IS NULL OR patientFirstName like 
'%'+LTRIM(RTRIM(@searchInput))+'%'
     OR LTRIM(RTRIM(@searchInput)) IS NULL OR patientMiddleName like 
'%'+LTRIM(RTRIM(@searchInput))+'%'
     OR LTRIM(RTRIM(@searchInput)) IS NULL OR patientLastName like 
'%'+LTRIM(RTRIM(@searchInput))+'%')

http://sqlfiddle.com/#!18/93ce1/33

注意：我无法像在旧版SQL Server上那样使用TRIM

Answer 1

我不能像在旧版SQL Server上那样使用TRIM

好吧，您可以将 REPLACE() 函数（从SQL Server 2008开始）用作belew：

DECLARE @T TABLE
(
    patientFirstName VARCHAR(50)
);

INSERT INTO @T VALUES
('     Patient       '),
('     John          '),
('     Demo User     ');

SELECT *
FROM @T
WHERE UPPER(REPLACE(patientFirstName, ' ', '')) = UPPER('demouser');

如果您还要查找其他列，则只需添加OR，例如：

WHERE UPPER(REPLACE(patientFirstName, ' ', '')) = UPPER('demouser')
OR UPPER(REPLACE(patientMiddleName, ' ', '')) = UPPER('demouser')
OR UPPER(REPLACE(patientLastName, ' ', '')) = UPPER('demouser');

Answer 2

不可保留，但应返回所需结果

....
WHERE (@startTime IS NULL OR startdate >= @startTime)
AND   (@endTime   IS NULL OR enddate   <= @endTime)
AND   charindex(@searchInput,replace(concat(patientFirstName,'-',patientMiddleName,'-',patientLastName),' ',''))>0

注意：'-'是可选的，它们只是防止渗色

Answer 3

您可以使用以下内容：

SET @searchInput = 'demouser'
SET @searchInput = LOWER(LTRIM(RTRIM(@searchInput)))


SELECT *
FROM (
SELECT
    LTRIM(RTRIM(REPLACE([patientFirstName],' ','')))        patientFirstName
,   LTRIM(RTRIM(REPLACE([patientMiddleName],' ','')))   patientMiddleName
,   LTRIM(RTRIM(REPLACE([patientLastName],' ','')))     patientLastName
,   [startdate]
,   [enddate]
FROM PatientDemoTable
) D
WHERE
( 
        ISNULL(@searchInput,LOWER(patientFirstName))    = LOWER(patientFirstName)
    OR  ISNULL(@searchInput,LOWER(patientMiddleName))   = LOWER(patientMiddleName)
    OR  ISNULL(@searchInput,LOWER(patientLastName))     = LOWER(patientLastName)
)
AND 
(
        ISNULL(@startTime, startdate) >= startdate
    AND ISNULL(@endTime, enddate) <= enddate
)

LTRIM()和RTRIM()仅用于删除空格的保证，而REPLACE()也将删除所有空格。 LOWER()将所有字母都大写（如果排序规则区分大小写，则这只是数据库排序规则的一种变通方法。）

ISNULL()将用列数据替换@searchInput，因此如果它为NULL，它将带走所有数据（另一种解决方法将避免使用LIKE表达式。）

无法使用LTRIM和RTRIM使用空格搜索记录

3 个答案: