Question

我有一个带有文件名的示例数组：

$test_array = array (
'video-start-1537482914-stop-1537483670.zip',
'video-start-1537533156-stop-1537534299.zip',
'video-start-1537534300-stop-1537534630.zip',
'video-start-1537090052-stop-1537091001.zip'
);

我想从每个文件中获取开始时间戳，然后将它们按数组排序。我尝试了preg_match，但它仅适用于字符串，不适用于数组。我该如何实现？

Answer 1

public function testSort()
  {
    $test_array = array (
      'video-start-1537482914-stop-1537483670.zip',
      'video-start-1537533156-stop-1537534299.zip',
      'video-start-1537534300-stop-1537534630.zip',
      'video-start-1537090052-stop-1537091001.zip'
    );

    usort($test_array, function($a, $b) {
      return ((int)explode('-',$a)[2] < (int)explode('-',$b)[2]) ? -1 : 1;
    });

    foreach($test_array as &$line) {
      echo $line . PHP_EOL;
    }

  }

Answer 2

尝试一下：

<?php

$test_array = array(
    'video-start-1537482914-stop-1537483670.zip',
    'video-start-1537533156-stop-1537534299.zip',
    'video-start-1537534300-stop-1537534630.zip',
    'video-start-1537090052-stop-1537091001.zip'
);

foreach ($test_array as $item){
    preg_match('/video-start-(.*?)-stop-/', $item, $match);
    $timespan[] = $match[1];
}

//sorts an associative array in ascending order.
asort($timespan);

var_dump($timespan);

?>

输出start timestamp：

array (size=4)
  3 => string '1537090052' (length=10)
  0 => string '1537482914' (length=10)
  1 => string '1537533156' (length=10)
  2 => string '1537534300' (length=10)

PHP-从文件名获取时间戳并按数组排序

2 个答案: