Python for循环输出到列表

Question

def factors(n):
for i in reversed(range(1, n+1)):
    if n % i ==0:
        print(i)

此代码当前在换行符ex中输出数字的因数。 factor（18）输出18 9 6等。...输入

print("factors for 18 are:", factors(18))

返回

的列表

factors of 18: [18,9,6,3,2,1]

我的函数中没有print（i）。

Answer 1

def factors(n):
  ret = [] #Make an empty array to store number factors
  for i in reversed(range(1, n+1)):
    if n % i ==0:
      ret.append(i) #append factors
  return ret #return array of factors

print("Factors of 18", factors(18))