Question

如果当前日期是今天，我在网上找不到有关添加课程的正确答案。

我有一个事件列表，如果今天匹配，我想在事件日期中添加课程。

输出

12  13 September 2018   Thursday    Workout
2   22 September 2018   Saturday    Workout <-- today
1   25 September 2018   Tuesday     Meeting
3   06 October 2018     Saturday    Meeting
13  11 October 2018     Thursday    Meeting
4   22 October 2018     Monday      Workout
7   27 October 2018     Saturday    Meeting
5   05 November 2018    Monday      Workout
14  07 November 2018    Wednesday   Meeting

HTML

<table class="calendar">
    <thead>
        <th>#</th>
        <th>Date</th>
        <th>Day</th>
        <th>Item</th>
    </thead>
    <?php while($row = mysqli_fetch_assoc($result)) :
        $cId = $row['c_id'];
        $cDate = $row['c_datetime'];
        $ciName = $row['ci_name'];
        $ccName = $row['cc_name'];
        ?>
        <tr>
            <td><?php echo $cId; ?></td>
            <td class="day"><?php echo dateFormatFullMonth($cDate); ?></td>
            <td><?php echo dateFormatDay($cDate); ?></td>
            <td><?php echo $ciName; ?></td>
        </tr>
    <?php endwhile; ?>
</table>

下面的这个与日期匹配。

$('table.calendar tr td.day').eq(new Date().getDay()).parent().addClass('bg-success');

Answer 1

所以我在这里找到了答案。

https://stackoverflow.com/a/33935926/5413283

<!-- Today is 25 Sep 18 -->
<div id="datecontainer">
    <p data-date="2018-9-20">2018-09-20</p>
    <p data-date="2018-9-21">2018-09-21</p>
    <p data-date="2018-9-22">2018-09-22</p>
    <p data-date="2018-9-23">2018-09-23</p>
    <p data-date="2018-9-24">2018-09-24</p>
    <p data-date="2018-9-25">2018-09-25</p> <!-- this will have the class -->
</div>

$(function() {
    var d =new Date();
    var curmonth = d.getMonth()+1;
    var curDate = d.getFullYear() + "-" + curmonth + "-" +d.getDate();
    $("#datecontainer p[data-date="+curDate+"]").addClass("today");
});

还有两个月的数字

var curDate = d.getFullYear() + "-0" + curmonth + "-" +d.getDate();

如果日期是今天，则添加jquery类

1 个答案: