因此,我正在尝试构建一个Meme-Creator。您已经可以从画布上传图片作为background-img。现在,我正在尝试制作Meme字体,但它实际上并没有工作。但是,这在图片中造成了很大的差距。感谢您的帮助和关注! :D
var canvas = document.getElementById("meme-canvas");
var ctx = canvas.getContext("2d");
var width = canvas.width;
var height = canvas.height;
function readImage() {
if (this.files && this.files[0]) {
var FR = new FileReader();
FR.onload = function(e) {
var img = new Image();
img.addEventListener("load", function() {
ctx.clearRect(0, 0, width, height);
canvas.width = img.width;
canvas.height = img.height;
ctx.drawImage(img, 0, 0);
});
img.src = e.target.result;
};
FR.readAsDataURL(this.files[0]);
}
}
function Text() {
ctx.clearRect(0, 0, width, height);
var textT = document.getElementById("top-text").value;
var textB = document.getElementById("bottom-text").value;
ctx.font = "60px Impact";
ctx.lineWidth = 3;
ctx.strokeText(textT, 10, 65);
ctx.strokeText(textB, 10, 400);
}
document.getElementById("image-input").addEventListener("change", readImage, false);
<input type="file" id="image-input" accept="image/*">
<input type="text" id="top-text" oninput="Text()">
<input type="text" id="bottom-text" oninput="Text()">
<canvas style="position: absolute; width: 400px; top: 100px; left: 10px;" id="meme-canvas"></canvas>
答案 0 :(得分:2)
我对您的脚本进行了一些更改。因为您需要多次绘制图像,所以我编写了一个绘制图像的函数。每当2个文本输入之一更改其值时,以及每次必须重新绘制所有内容时,都会清除画布。
textT和textB也只能声明一次。您无需在Text函数中声明它们。
我需要多次使用字体大小(60),因此我已将变量fontSize = 60
设置为
由于您不知道画布的大小(取决于上传的图像的大小),因此需要计算底部文本textB = height - fontSize/2
的位置,其中height是画布的高度:{{ 1}}
我希望它有用。
height = canvas.height = img.height;
var canvas = document.getElementById("meme-canvas");
var ctx = canvas.getContext("2d");
var width = (canvas.width = 400);
var height = (canvas.height = 400);
var fontSize = 60;
var img = new Image();
var textT = document.getElementById("top-text");
var textB = document.getElementById("bottom-text");
function readImage() {
if (this.files && this.files[0]) {
var FR = new FileReader();
FR.onload = function(e) {
img.addEventListener("load", function() {
width = canvas.width = img.width;
height = canvas.height = img.height;
drawImage();
});
img.src = e.target.result;
};
FR.readAsDataURL(this.files[0]);
}
}
function drawImage() {
ctx.drawImage(img, 0, 0);
}
function Text() {
ctx.font = fontSize + "px Impact";
ctx.textAlign = "center";
ctx.lineWidth = 3;
ctx.clearRect(0, 0, width, height);
drawImage();
ctx.strokeText(textT.value, width / 2, 65);
ctx.strokeText(textB.value, width / 2, height - fontSize/2);
}
document
.getElementById("image-input")
.addEventListener("change", readImage, false);
textT.addEventListener("input", Text);
textB.addEventListener("input", Text);
canvas{position: absolute; left: 10px; top:60px;border:1px solid #d9d9d9;}
答案 1 :(得分:1)
我遇到的一些问题:
这是代码:
var canvas = document.getElementById("meme-canvas");
var ctx = canvas.getContext("2d");
var img = new Image();
function readImage() {
if (this.files && this.files[0]) {
var FR = new FileReader();
FR.onload = function(e) {
img.addEventListener("load", function() {
canvas.width = img.width;
canvas.height = img.height;
draw();
});
img.src = e.target.result;
};
FR.readAsDataURL(this.files[0]);
}
}
function draw() {
var textT = document.getElementById("top-text").value;
var textB = document.getElementById("bottom-text").value;
ctx.clearRect(0, 0, canvas.width, canvas.height);
ctx.font = "60px Impact";
ctx.shadowColor = "white"
ctx.shadowOffsetX = ctx.shadowOffsetY = 2
ctx.lineWidth = 3;
if (img) ctx.drawImage(img, 0, 0);
ctx.strokeText(textT, 10, 45);
ctx.strokeText(textB, 10, canvas.height -10);
}
document.getElementById("image-input")
.addEventListener("change", readImage, false);
<input type="file" id="image-input" accept="image/*"><br>
<input type="text" id="top-text" placeholder="Top text" oninput="draw()"><br>
<input type="text" id="bottom-text" placeholder="Bottom text" oninput="draw()"><br>
<canvas id="meme-canvas"></canvas>