Question

MySQL表具有3列-区域，月份和收入，其值如下：

我编写了一个查询，将每个地区的收入按月分组

SET @sql = NULL;
SELECT GROUP_CONCAT(DISTINCT
         CONCAT("SUM(CASE WHEN region = ", QUOTE(region)," THEN revenue ELSE 0 END) AS ",
         CONCAT('`', region, '`')))
  INTO @sql
  FROM (SELECT * FROM TABLE1 WHERE region IS NOT NULL AND region <> '') RTD;


SET @sql = CONCAT("SELECT DATE_FORMAT(month, '%M-%Y') as Months, ", @sql, "
,SUM(revenue) as `Grand Total` FROM TABLE1
GROUP BY month ORDER BY month ASC" );

PREPARE region_stmt FROM @sql;
EXECUTE region_stmt;

在命令行和续集pro中产生这样的结果（这是期望的结果）

Query result

但是当我对带有python 2.7光标的Django 1.8使用相同的查询时，会产生错误

ProgrammingError：（1064，u'您的SQL语法有错误；请查看与您的MySQL服务器版本相对应的手册，以在\'SELECT GROUP_CONCAT（DISTINCT \ r \ n CONCAT（“ SUM （当region = \'“，第2行的'regio \'时为例）

我也使用了单引号而不是Quote（），但是得到了相同的结果

CONCAT("SUM(CASE WHEN region = '", region,"' THEN revenue ELSE 0 END) AS ",

Python代码

from django.db import connections
crsr = connections['rmd'].cursor()
crsr.execute(query)

Answer 1

似乎您已经在转义引号和换行符，因此请避免在regiorn周围避免quote（）

SET @sql = NULL;
SELECT GROUP_CONCAT(DISTINCT
     CONCAT("SUM(CASE WHEN region = ", region," THEN revenue ELSE 0 END) AS ",
     CONCAT('`', region, '`')))
INTO @sql
FROM (SELECT * FROM TABLE1 WHERE region IS NOT NULL AND region <> '') RTD;

您应该检查应用程序中sqlcode的真实内容，并使动态命令构建适应运行时应用程序环境的功能

MySQL预处理语句在Django上产生错误，但可在命令行中使用

1 个答案: