Question

我的表choosen_emails_1，choosen_emails_2，choosen_emails_3，booking_address，booking_number，booking_message，{{1} }，booking_date和request_date

user_email循环迭代并打印除for和user_email以外的所有内容

我在控制器类中使用了booking_number语句来检查查询选择器是否选择了表中的所有列，并打印了所有9列

因此后端代码没有问题。谁能告诉我这个jquery是否有任何问题！代码

Println

data = "";

myfunction = function() {
  $('.tablecontainer').show();
  load();
}

load = function() {

  $.ajax({
      url: 'updatedservicerequests',
      type: 'POST',
      data: {}, // function to get the value from jsp page and send it to mapped class function//
      success: function(response) { // if the backend process is success then the function will run by getting the response as its parameter//
        alert(response.message);
        data = response.data;
        alert(response.data);
        $('.tr').remove();
        alert(response.data);
        $(function() {
            for (i = 0; i < response.data.length; i++) {

              $("#table").append(response.data[i].user_email + "'>" + response.data[i].booking_number + " </td> <td> " + response.data[i].booking_address + " </td> <td> " + response.data[i].booking_date + " </td> <td> " + response.data[i].booking_message + " </td> <td> " + response.data[i].request_date + " </td> <td> " + response.data[i].chosen_emails_1 + " </td> <td> " + response.data[i].chosen_emails_2 + " </td> <td> " + response.data[i].chosen_emails_3 + "</br>");


            }

            //to prevent (contact-submit) button from submitting form data since submit button has default action of submitting form

            $(document).ready(function() {
              $('#contact-submit').click(function(e) {

                return false;
              });
            });
          }
        });

    },
    error: function(response) {
      alert("unable to pull up any service request");
    }
  });

Answer 1

此行缺少这两个字段周围的/dev/urandom/标签，并且缺少整行周围的<td>标签。

<tr>

您也不应该在其中使用$("#table").append(response.data[i].user_email + "'>" + response.data[i].booking_number + " </td> <td> " + response.data[i].booking_address + " </td> <td> " + response.data[i].booking_date + " </td> <td> " + response.data[i].booking_message + " </td> <td> " + response.data[i].request_date + " </td> <td> " + response.data[i].chosen_emails_1 + " </td> <td> " + response.data[i].chosen_emails_2 + " </td> <td> " + response.data[i].chosen_emails_3 + "</br>");，这甚至不是有效的标签，并且它当然不属于</br>。

正确的代码是：

<table>

for循环不会遍历ajax jquery

1 个答案: