AWS API Gateway和Lambda返回新的错误状态

Question

因此，当您从scracth创建新的lambda时，将获得以下默认index.js内联代码：

(Remi_Brun)(_.+)([a-zA-Z0-9-_]{11}.en.vtt)

此lambda由api网关端点使用。如果某些情况不太正确，返回错误代码的正确方法是什么？网关会处理它还是只将上面的状态更改为新的错误代码？

Answer 1

1xx (Informational): The request was received, continuing process
2xx (Successful): The request was successfully received, understood, and accepted
3xx (Redirection): Further action needs to be taken in order to complete the request
4xx (Client Error): The request contains bad syntax or cannot be fulfilled
5xx (Server Error): The server failed to fulfill an apparently valid request

这只是返回200响应，这是成功的响应。您只需要根据您的实现返回正确的代码即可。我想这就是您要的。

有关状态码的更多信息，您可以阅读此Wiki。 https://en.wikipedia.org/wiki/List_of_HTTP_status_codes

但是由于您在询问实施问题，因此我将执行以下操作

exports.handler = async (event) => {
    // TODO implement
    let statusCode = 200;
    let message = 'success';
    ... // do stuff
    statusCode = 400 // something went wrong
    const response = {
        statusCode: statusCode,
        body: JSON.stringify(message)
    };
    return response;
};

取决于您希望应用程序如何扩展，这完全取决于您。请记住，永远不要重复代码。保持模块化。

此外，您还可以在函数中声明

// Somewhere else
response = function (statusCode, message) {
    return {
     statusCode: statusCode,
     body: JSON.stringify(message)
    };
};

exports.handler = async (event) => {
    // TODO implement
    let statusCode = 200;
    let message = 'success';
    ... // do stuff
    statusCode = 400 // something went wrong

    return response(statusCode, message);
};

从AWS中检出错误处理模式。 除非您已经阅读过，否则这将是一个不错的开始。 https://aws.amazon.com/blogs/compute/error-handling-patterns-in-amazon-api-gateway-and-aws-lambda/

基本上，您需要满足以下条件

exports.handler = (event, context, callback) => {
    var myErrorObj = {
        errorType : "InternalServerError",
        httpStatus : 500,
        requestId : context.awsRequestId,
        message : "An unknown error has occurred. Please try again."
    }
    callback(JSON.stringify(myErrorObj));
};