Question

很抱歉，没有足够的信息，但是我仍在学习SQL，希望对您有所帮助。

我想在视图上设置触发器，该触发器在更新或插入后激活，然后更新另一个表上的特定列。我拥有这两个数据集的唯一方法是从日期和人的名字开始。否则，他们不会共享任何其他信息。

Answer 1

这就是我发现的工作方式，感谢您提供的任何帮助。这可能并不理想，因此，如果有任何建议，请随时发表评论。

CREATE TRIGGER triggername
ON TABLE1
AFTER INSERT, UPDATE
AS 
BEGIN
DECLARE @INS NVARCHAR(50)
SELECT @INS = NAMECOLUMN FROM INSERTED
WHERE DESCRIPTION = 'BRIEF DESCRIPTION' 
END
IF @INS = ‘Last, First’

BEGIN

UPDATE TABLE1
SET DESTINATIONCOLUMN  =  EXAMPLE.CT

FROM (SELECT COUNT(*) AS CT FROM TABLE2 WHERE NAMECOLUMN = ‘Last, First’) EXAMPLE
WHERE DESCRIPTION = 'BRIEF DESCRIPTION' AND NAMECOLUMN = ‘Last, First’
END
BEGIN

Answer 2

TRIGGER

USE [DATABASENAME]
GO

CREATE TRIGGER [TRIGGERNAME] ON [VIEWNAME] 
INSTEAD OF INSERT, UPDATE, DELETE 
AS 

IF @@ROWCOUNT = 0 -- exit trigger
    RETURN;

IF EXISTS(SELECT * FROM inserted)
BEGIN
    IF EXISTS(SELECT * FROM deleted)
        -- to update in another table
        UPDATE a
        SET a.xyz = i.xyz
        FROM another_table a
        INNER JOIN inserted i
        ON a.column = i.column
    ELSE
        -- to insert in another table
        INSERT INTO [dbo].[another_table]
        SELECT * FROM inserted
END
ELSE
BEGIN
    -- to delete from another table
    DELETE a
    FROM another_table a
    INNER JOIN deleted d
    ON a.column = d.column  
END

如何在SQL Server的视图上设置触发器，以将列的数据输入/更新到表中？

2 个答案: