为了使抖动集成测试更易于阅读,我试图使用机器人模式来编写如下代码(链接):
test('home', () async {
driver = await FlutterDriver.connect();
HomeRobot(driver)
.seesFromPlacesField()
.seesToPlacesField()
.seesNotSwapButton();
});
基本机械手类如下:
class RobotBase {
RobotBase(this.driver, this.finder);
final FlutterDriver driver;
final SerializableFinder finder;
sees(String valueKey) async {
print("sees: $valueKey");
await driver.waitFor(find.byValueKey(valueKey));
}
seesNot(String valueKey) async {
print("sees not: $valueKey");
await driver.waitForAbsent(find.byValueKey(valueKey));
}
}
还有一个像这样的实际机器人:
class HomeRobot extends Robot {
HomeRobot(FlutterDriver driver)
: super(driver, find.byValueKey(home_keys.page));
Future<HomeRobot> seesFromPlacesField() async {
await sees(home_keys.fromPlaceField);
return this;
}
Future<HomeRobot> seesToPlacesField() async {
await sees(home_keys.toPlaceField);
return this;
}
Future<HomeRobot> seesNotSwapButton() async {
await seesNot(home_keys.swapButton);
return this;
}
Future<HomeRobot> seesSwapButton() async {
await sees(home_keys.swapButton);
return this;
}
}
但是目前可以正常运行的测试是这样的(theing):
test('home', () async {
driver = await FlutterDriver.connect();
HomeRobot r = HomeRobot(driver);
await r.seesFromPlacesField().then((r) async {
await r.seesToPlacesField().then((r) async {
await r.seesNotSwapButton();
});
});
});
或者这个(等待中):
test('home', () async {
driver = await FlutterDriver.connect();
HomeRobot r = HomeRobot(driver);
r = await (await (await r
.seesFromPlacesField())
.seesToPlacesField())
.seesNotSwapButton();
});
关于如何很好地进行链接的任何想法?
解决方案
机器人负责“工作”:
class HomeRobot extends Robot {
HomeRobot(FlutterDriver driver, Future<void> work) : super(driver, work);
HomeRobot seesFromPlacesField() {
work = work.then((_) async => await seesKey(keys.homePageFromPlaceField));
return this;
}
SearchRobot tapsOnFromPlacesField() {
work = work.then((_) async => await tapsOnKey(keys.homePageFromPlaceField));
return SearchRobot(driver, work);
}
// ...
}
class SearchRobot extends Robot {
SearchRobot(FlutterDriver driver, Future<void> work) : super(driver, work);
SearchRobot seesBackButton() {
work = work.then((_) async => await seesTooltip(Robot.backButtonTooltip));
return this;
}
HomeRobot tapsOnBackButton() {
work = work.then((_) async => await tapsOnTooltip(Robot.backButtonTooltip));
return HomeRobot(driver, work);
}
// ...
}
基类提供所有基本步骤:
class Robot {
Robot(this.driver, this.work);
final FlutterDriver driver;
Future<void> work;
seesKey(String key) async {
print("sees key: $key");
await driver.waitFor(find.byValueKey(key));
}
tapsOnKey(String key) async {
print("taps on key: $key");
await driver.tap(find.byValueKey(key));
}
// ...
}
一个测试用例如下:
test('home', () async {
HomeRobot robot = HomeRobot(driver, Future.value(null));
await robot
.seesFromPlacesField()
.seesToPlacesField()
.seesNotSwapButton()
.tapsOnFromPlacesField()
.seesSearchField()
.seesBackButton()
.tapsOnBackButton()
.seesFromPlacesField()
.work;
});
答案 0 :(得分:0)
我试图修改您想要的API-但是我添加了第二个类。在这种情况下,机器人包含与驱动程序交互所需的实际异步命令。相应的“ Work”类包含一个Future,当您在其上调用方法时,它会逐渐建立。这些方法依次调用了机器人上的实际异步工作,但是我们可以继续调用它们而无需等待机器人完成。最后,我们返回最终的未来,可以等待所有工作完成。
请注意,在这种情况下,我们无法使用..
语法,因为我们需要对Work类返回的值调用await
。
final driver = await FlutterDriver.connect();
final robot = HomeRobot(driver);
await robot.start()
.seesFromPlacesField()
.seesToPlacesField()
.seesNotSwapButton()
.work();
class HomeRobot {
HomeRobot(this.driver);
final FlutterDriver driver;
/// Create a new work class which builds up a Future.
HomeRobotWork start() => new HomeRobotWork(this);
Future<void> _seesFromPlacesField() async { ... }
Future<void> _seesToPlacesField() async { ... }
Future<void> _seesNotSwapButton() async { ... }
}
class HomeRobotWork {
HomeRobotWork(this.robot);
final HomeRobot robot;
Future<void> _result = new Future.value(null);
/// Add a future onto the result value
void seesFromPlacesField() {
_result = _result.then((_) => robot._seesFromPlacesField());
return this;
}
void seesToPlacesField() {
_result = _result.then((_) => robot._seesToPlacesField());
return this;
}
void seesNotSwapButton() {
_result = _result.then((_) => robot._seesNotSwapButton());
return this;
}
Future<void> work() => _result;
}