Question

我正在尝试使用用户名和全名属性更新名为User的对象；我的模特在下面。

class User(models.Model):
"""docstring for User"""

fullname = models.TextField()
username = models.TextField()
password = models.TextField()
createdDate = models.DateTimeField(default=timezone.now)
publishedDate = models.DateTimeField(blank=True, null=True)

def publish(self):
    self.publishedDate = timezone.now
    self.save()

def __str__(self):
    return str("\npk= " + self.pk + " | fullname= " + self.fullname + " | username= " + self.username + "\n")

我已经创建了一个编辑页面，并且能够通过request.POST [“ fullname”]和request.POST [“ username”]从该页面中获取值。

我的问题是，如何更新整个对象，而不必在update中指定特定的属性，或者不获取对象并设置新值并保存对象；我的看法在下面。

def editUserByID(request, userID):
    if (request.method == "POST"):
        if (request.POST["userID"] != '' and request.POST["fullname"] != '' and request.POST["username"] != ''):
            user1 = User(
                pk=request.POST["userID"],
                fullname=request.POST["fullname"],
                username=request.POST["username"]
            )

        print(user1)

        # this only updates 1 property, so for multiple properties I would have to write multiple statements
        User.objects.filter(pk=user1.pk).update(fullname=user1.fullname) 

        # is this possible? send the entire object and have it update the DB
        User.objects.filter(pk=user1.pk).update(user1)  

        # this is how I was able to save it, but have to get the existing object again, assign the new values and then save
        updateUser = User.objects.get(pk=user1.pk)
        updateUser.fullname=user1.fullname
        updateUser.username=user1.username
        updateUser.save()

else:
    user2 = User.objects.get(pk=userID)
    return render (request, 'helloworld/editUser.html', {'user': user2})
return redirect('listUsers')

PS：到目前为止，我一直在使用Java和.NET，但是对于Python / Django来说是全新的，所以我们将不胜感激。

Answer 1

这主要是错误的方法。首先，无需创建var jsonObject = JSON.stringify({ "api_key":"8a661f60-5873-11e5-a4c8-7f9bc5b8cb08" }); var postheaders = { 'content-Type':'application/json', 'content-Length':Buffer.byteLength(jsonObject,'utf8') // "api_key":"8a661f60-5873-11e5-a4c8-7f9bc5b8cb08" }; var optionspost = { host:'config.remote.host', port:'config.remote.port', path:'api/get_all_domains', method:'POST', headers:postheaders }; console.info('Options prepared:'); console.info(optionspost); console.info('Do the POST call'); var reqPost = https.request(optionspost, function(res) { console.log("statusCode: ", res.statusCode); console.log("headers: ", res.headers); res.on('data', function(d) { console.info('POST result:\n'); process.stdout.write(d); console.info('\n\nPOST completed'); }); }); reqPost.write(jsonObject); reqPost.end(); reqPost.on('error', function(e) { console.error(e); });；如果要更新现有对象，则应直接在此处设置值。

但是在Django中执行此操作的方法是使用ModelForm。这样做有很多优点，特别是它将验证您的输入，检查是否已提供所有必填字段以及它们的类型正确。您可以在实例化表单时将现有用户作为user1参数传递，然后在保存表单时更新该实例。

instance

此外，我赞成Risadinha的观点，即您不应创建自己的用户模型。使用Django的内置身份验证框架。

Answer 2

您可以像这样在一行中完成此操作：

User.objects.filter(pk=user1.pk).update(fullname=user1.fullname, 
username=user1.username)

更新模型的另一种方法是使用如下形式：

# You can get user based on your logic
user = request.user
# 'EditUserForm' is the custom form, read more about django model forms if you already have not, https://docs.djangoproject.com/en/2.1/topics/forms/modelforms/#the-save-method
user_form = EditUserForm(request.POST, instance=user)
if user_form.is_valid():
    user_form.save()
else:
    user2 = User.objects.get(pk=userID)
    return render (request, 'helloworld/editUser.html', {'user': user2})

return redirect('listUsers')

Django更新整个对象（行）

2 个答案: