我想为一个人(姓名)的最近3个事件创建滚动平均值。
我有想要使用这3个事件中最新事件的日期。有些人可能比其他人少td {
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,这没关系。
创建数据框的代码:
DF
DF:
library(dplyr)
# Create DataFrame
df<- data.frame(name=c('CAREY.FAKE','CAREY.FAKE','CAREY.FAKE','CAREY.FAKE','CAREY.FAKE','CAREY.FAKE',
'JOHN.SMITH','JOHN.SMITH','JOHN.SMITH','JOHN.SMITH','JOHN.SMITH','JOHN.SMITH',
'JEFF.JOHNSON','JEFF.JOHNSON','JEFF.JOHNSON','JEFF.JOHNSON',
'SARA.JOHNSON','SARA.JOHNSON','SARA.JOHNSON','SARA.JOHNSON'
),
GA=c(2,2,2,2,2,20,2,2,2,2,2,20,2,2,2,20,2,2,2,20),
SV=c(2,2,2,2,2,20,2,2,2,2,2,20,2,2,2,20,2,2,2,20),
GF=c(2,2,2,2,2,20,2,2,2,2,2,20,2,2,2,20,2,2,2,20),
SA=c(2,2,2,2,2,20,2,2,2,2,2,20,2,2,2,20,2,2,2,20),
date=c("10/20/2016","10/19/2016","10/18/2016","10/17/2016","10/16/2016","10/15/2016",
"10/20/2016","10/19/2016","10/18/2016","10/17/2016","10/16/2016","10/15/2016",
"10/20/2016","10/19/2016","10/18/2016","10/17/2016",
"10/20/2016","10/19/2016","10/18/2016","10/17/2016"
),
stringsAsFactors = FALSE)
创建滚动平均值的代码:
name GA SV GF SA date
CAREY.FAKE 2 2 2 2 10/20/2016
CAREY.FAKE 2 2 2 2 10/19/2016
CAREY.FAKE 2 2 2 2 10/18/2016
CAREY.FAKE 2 2 2 2 10/17/2016
CAREY.FAKE 2 2 2 2 10/16/2016
CAREY.FAKE 20 20 20 20 10/15/2016
JOHN.SMITH 2 2 2 2 10/20/2016
JOHN.SMITH 2 2 2 2 10/19/2016
JOHN.SMITH 2 2 2 2 10/18/2016
JOHN.SMITH 2 2 2 2 10/17/2016
JOHN.SMITH 2 2 2 2 10/16/2016
JOHN.SMITH 20 20 20 20 10/15/2016
JEFF.JOHNS 2 2 2 2 10/20/2016
JEFF.JOHNS 2 2 2 2 10/19/2016
JEFF.JOHNS 2 2 2 2 10/18/2016
JEFF.JOHNS 20 20 20 20 10/17/2016
SARA.JOHNS 2 2 2 2 10/20/2016
SARA.JOHNS 2 2 2 2 10/19/2016
SARA.JOHNS 2 2 2 2 10/18/2016
SARA.JOHNS 20 20 20 20 10/17/2016
错误:
df_next <- df %>%
group_by(name) %>%
summarise(last_three_mean = mean(tail(GA,SV,GF,SA, 3))
所需结果:
Error in summarise_impl(.data, dots) :
Evaluation error: length(n) == 1L is not TRUE.
答案 0 :(得分:1)
我们可以按日期将arrange
summarise_at
,然后按{name}分组后使用mean
获得多列的library(dplyr)
library(lubridate)
df %>%
group_by(name) %>%
arrange(name, mdy(date)) %>%
summarise_at(2:5, funs(mean(tail(., 3))))
#or select the column by matching the name pattern
#summarise_at(vars(matches("^[A-Z]{2}$")), funs(mean(tail(., 3))))
# A tibble: 4 x 5
# name GA SV GF SA
# <chr> <dbl> <dbl> <dbl> <dbl>
#1 CAREY.FAKE 2 2 2 2
#2 JEFF.JOHNSON 2 2 2 2
#3 JOHN.SMITH 2 2 2 2
#4 SARA.JOHNSON 2 2 2 2
top_n
或者另一种选择是利用summarise_at
然后执行df %>%
group_by(name) %>%
top_n(mdy(date), n = 3) %>%
summarise_at(2:5, mean)
class IndexController < ApplicationController
def index
sleep(10)
render text: "done"
end
end