当我这样传递文件名时,它不会获取数据..如何在方法中动态传递fileName呢?
public static String fetchData(int index,int rowNum, int cellNum,String FileName) throws FileNotFoundException {
File filePath = new File(System.getProperty("user.dir") + "/InEdge_Files/ExcelData/" + FileName + ".xlsx");
fis = new FileInputStream(filePath);
sheet = workbook.getSheetAt(index);
value = sheet.getRow(rowNum).getCell(cellNum).getStringCellValue();
return value;
}
...传递我使用的数据时,driver.get(fetchData(0,1,2,“ Data”);
答案 0 :(得分:0)
String urlToOpen = fetchData(0,1,2,"Data");
driver.navigate().to(urlToOpen);