Question

j查询函数在克隆后计算日期时遇到问题，我需要自动计算用户选择签入和签出日期并将其放入文本框后的天数，它适用于第一行，但不适用于克隆的行

<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script src="js/jquery-1.3.2.min.js" type="text/javascript"></script>
        <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js"></script>
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
        <script src="https://ajax.aspnetcdn.com/ajax/jQuery/jquery-3.3.1.min.js"></script>
        <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.0/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js" type="text/javascript"></script>
 <script type="text/javascript">
        function GetDays(){
                var dropdt = new Date(document.getElementById("drop_date").value);
                var pickdt = new Date(document.getElementById("pick_date").value);
                return parseInt((dropdt - pickdt) / (24 * 3600 * 1000));
        }
        function cal(){
        if(document.getElementById("drop_date")){
            document.getElementById("numdays2").value=GetDays();
        }  
    }
    </script>
<script type="text/javascript">
$(document).ready(function(){
  var genroomid = 2;    
  $( ".add-row" ).click(function(){
      var $clone = $( "ul.personal-details" ).first().clone();
      var $input = $clone.find('#roomid');
      $input.val(genroomid).attr('genroomid' , +genroomid)  
      $clone.append( "<button type='button' class='remove-row'>-</button>" );
      $clone.insertBefore( ".add-row" );
      genroomid++; // increase id by 1
  });
  $( ".form-style-9" ).on("click", ".remove-row", function(){
      $(this).parent().remove();
      genroomid--;
  });
  });
  </script>
  </head>
  <body>
  <form name="form_reservations" method="post" action="add.php">
  <span class="form-style-9">
        <ul class="personal-details">
                <label for="roomid">RoomID</label>
                <input name="roomid[]" type="text" class="stretchnights" id="roomid"  readonly="readonly" value="1">    
                <label for="chkin">Check IN</label>
                <input class="stretchdate" size="15" width="15"  id="pick_date" type="date"  name="chkin[]"  onchange="cal()" required/>
                <label for="chkout">Check Out</label>
                <input class="stretchdate"  id="drop_date" type="date" name="chkout[]"  onchange="cal()" required/>
                <label for="nights">Nights    
                <input class="stretchnights" type="text"   id="numdays2"  name="nights[]" readonly /></label>
       </ul>
        <button type="button" class="add-row">+ New Client</button>
      </span>
</form>
</body>

Answer 1

您共享的代码段中存在很多问题，您试图在原始元素中使用ID并进行克隆，这对于您的用例来说是个坏主意。您可以做的是将其转换为类，然后在cal（）中传递目标元素。通过这样做，您可以找到该元素。而且您的夜晚标签未正确关闭

替换您现有的脚本块

<script type="text/javascript">
        function GetDays(target){
                var dropdt = new Date($(target).find(".drop_date").val());
                var pickdt = new Date($(target).find(".pick_date").val());
                return parseInt((dropdt - pickdt) / (24 * 3600 * 1000));
        }
        function cal(target){   
            console.log($(target).parent(), $(target).parent().find('numdays2'));
            $(target).parent().find('.numdays2').val(GetDays($(target).parent()));
        }  
    </script>

并以此替换您的.personal-details html块

<ul class="personal-details">
        <label for="roomid">RoomID</label>
        <input name="roomid[]" type="text" class="stretchnights" id="roomid"  readonly="readonly" value="1">    
        <label for="chkin">Check IN</label>
        <input  size="15" width="15"  id="pick_date" class="pick_date" type="date"  name="chkin[]"  onchange="cal(this)" required/>
        <label for="chkout">Check Out</label>
        <input  id="drop_date" type="date" name="chkout[]"  class="drop_date" onchange="cal(this)" required/>
        <label for="nights">Nights  </label>  
        <input class="numdays2" type="text" id="numdays2" name="nights[]" readonly />

这应该可以解决问题

Answer 2

您在克隆的函数调用中使用了相同的ID。

javascript-jQuery函数不适用于克隆

2 个答案: