JavaScript从Array.forEach返回或中断

Question

我有一个数组，其中包含2个forEach循环，如下所示。

array1.forEach(o1 => unique_array2.forEach(o2 => {
 if (o1.uName == o2.uName && o1.uid == o2.uid) {
    //matches.push(o1);
    break;
   }
}));

如果找到匹配项，我想退出循环本身。我试图放置一个中断，但是它说非法的break语句自循环以来就存在。

我可以创建另一个假数组，然后将所有负值放置如下：

  if (o1.uName == o2.uName && o1.uid == o2.uid) {
    matches.push(o1);        
   }
  else{
     nonMatches.push(o1);
   } 

然后检查nonMatches数组，然后相应地返回。但是我试图避免这种情况，因为我的数组可能很大，一旦找到匹配项，我就想停止。

如果需要，这是我的摘录：

var array1 = [{
    id: 0,
    name: "adam",
    uName: "aSilver",
    uId: "123",
    table: "table1"
  },
  {
    id: 1,
    name: "john",
    uName: "jBerlin",
    uId: "456",
    table: "table1"
  }
];

var array2 = [{
    id: 0,
    name: "adam",
    uName: "aSilver, jBerlin",
    uId: "123, 456",
    createdBy: "auto",
    createdOn: "09/10/2018",
    desc: "none",
    table: "table1"
  },
  {
    id: 1,
    name: "john",
    uName: "aSilver, jBerlin",
    uId: "123, 456",
    createdBy: "auto",
    createdOn: "09/10/2018",
    desc: "none1",
    table: "table1"
  },
  {
    id: 0,
    name: "steve",
    uName: "aSilver, jBerlin, pParis",
    uId: "123, 456, 789 ", 
    createdBy: "auto ", 
    createdOn: "09 / 10 / 2018 ",
    desc: "none2", 
    table: "table2"
  },
  {
    id: 0,
    name: "nash",
    uName: "aSilver, jBerlin, pParis",
    uId: "123, 456, 789 ", 
    createdBy: "auto ", 
    createdOn: " 09 / 10 / 2018 ", 
    desc: "none3 ", 
    table: "table2"
  },
  {
    id: 0,
    name: "sand",
    uName: "aSilver",
    uId: "123",
    createdBy: "auto",
    createdOn: "09/10/2018",
    desc: "none4",
    table: "table3"
  }
];

obj = {};
array2.forEach(o => obj[o.table] = o);
unique_array2 = Object.keys(obj).map(k => obj[k]);
matches = [];
array1.forEach(o1 => unique_array2.forEach(o2 => {
    if (o1.uName == o2.uName && o1.uid == o2.uid) {
        //matches.push(o1);
        break;
    }
}));

console.log(matches);

还有其他解决方法吗？