Question

我想知道如何在函数范围之外打印函数的返回值。我在网上进行了研究，发现下面的帖子bu只是给我了arr，但该帖子未定义。有人能指出我正确的方向吗？ Console log not printing variable from function

//Creating an array of circles and fill them
    Random random = new Random();
    Circle circles[] = new Circle[20];
    for (int i = 0; i < 20; i++) {
        circles[i] = new Circle();
        circles[i].setRadius(30);
    }

    //Adding circles to pane on random position and give them random collers
    for (int i = 0; i < 20; i++) {
        Random randon = new Random();
        int randX = randon.nextInt((int) borderPane.getWidth() - 30);
        int randY = randon.nextInt((int) borderPane.getHeight() - 30);

        int rColor = 20 + randon.nextInt(235);
        int gColor = 20 + randon.nextInt(235);
        int bColor = 20 + randon.nextInt(235);

        borderPane.getChildren().add(circles[i]);
        circles[i].setCenterX(randX);
        circles[i].setCenterY(randY);
        circles[i].setFill(Color.rgb(rColor, gColor, bColor));
    }

Answer 1

您不应该自己单独调用multiplyAll，而应该将其分配给这样的变量：

var product = multiplyAll([[60,60],[24,365]]);

如果只想打印出结果，您可以做的另一件事是将函数调用放在console.log调用中，如下所示：

console.log("Print results of product" + multiplyAll([[60,60],[24,365]]));

打印功能超出本地范围的结果

1 个答案: