Question

我在Access中有下一张表：

ID  |   Name  |  Dog    |   Cat   |
===================================
1   | A       |   100   |   0     |
1   | B       |   0     |   100   |
1   | C       |   50    |   0     |
2   | A       |   100   |   0     |
2   | B       |   3     |   100   |
2   | C       |   3     |   50    |

通过查询，我需要这样显示它：

ID  |   Name  |  Dog    |   Cat   |
===================================
1   | A       |   100   |   0     |
1   | B       |   0     |   100   |
1   | C       |   50    |   0     |
1   | TOTAL   |   50    |   0     |
2   | A       |   100   |   0     |
2   | B       |   0     |   100   |
2   | C       |   0     |   50    |
2   | TOTAL   |   0     |   -50   |

如您所见，首先我将“狗”和“猫”列求和，然后对“狗-猫”求和，如果该值为正，则转到“狗”列，如果该值为负，则转到“猫”列。我是新来的，我已经检查过类似的问题，但是我想看看解决这个问题的最简单方法。谢谢！

到目前为止，我有

SELECT ID, Name, Dog, Cat
FROM Table
UNION 
SELECT ID, 'Total', SUM(Dog), SUM(Cat)
FROM Table
GROUP BY ID

我知道了：

ID  |   Name  |  Sum(Dog)|   Sum(Cat)|
======================================
1   | A       |   100    |   0       |
1   | B       |   0      |   100     |
1   | C       |   50     |   0       |
1   | TOTAL   |   150    |   100     |
2   | A       |   100    |   0       |
2   | B       |   0      |   100     |
2   | C       |   0      |   50      |
2   | TOTAL   |   100    |   150     |

Answer 1

您将使用union all和order by。在MS Access中，我认为是这样：

SELECT ID, Name, SUM(Dog), Sum(Cat)
FROM Table
GROUP BY ID, Name
UNION ALL
SELECT ID, "Total", SUM(Dog), Sum(Cat)
FROM Table
GROUP BY ID
ORDER BY IIF(Name = "Total", 1, 0), Name

您可以尝试使用子查询：

SELECT name, name, num_dogs, num_cats
FROM (SELECT ID, Name, SUM(Dog) as num_dogs, Sum(Cat) as num_cats, 1 as ord
      FROM Table
      GROUP BY ID, Name
      UNION ALL
      SELECT ID, "Total", SUM(Dog), Sum(Cat), 0 as ord
      FROM Table
      GROUP BY ID
     ) as t
ORDER BY ord, Name

使用GROUP BY内联的SUM列

1 个答案: