我正在尝试在我的if (input.hasNextInt()) {
lines = input.nextInt();
} else {
System.out.println("Please enter a number");
input.nextLine(); // Drop the current input up to the end-of-line marker
}
文件中定义多个WorkManagerTaskExecutor，但是我一直收到错误消息
applicationContext.xml我的bean定义很简单：
javax.naming.NoInitialContextException: Need to specify class name in environment or system
property, or as an applet parameter, or as an application resource file
我尝试使用<bean id="exo.cc.core.comms.external.SecondaryCommonJExecutor"
class="org.springframework.scheduling.commonj.WorkManagerTaskExecutor" scope="prototype">
<property name="workManagerName" value="java:comp/env/springSecondaryWorkManager"/>
<property name="workListener">
<bean class="exo.cc.core.util.LoggingListener"/>
</property>
</bean>
<bean id="exo.cc.core.comms.external.CommonJExecutor"
class="org.springframework.scheduling.commonj.WorkManagerTaskExecutor" scope="prototype">
<property name="workManagerName" value="java:comp/env/springWorkManager"/>
<property name="workListener">
<bean class="exo.cc.core.util.LoggingListener"/>
</property>
</bean>
作为有效措施，但这并不重要。当我只使用一个scope="prototype" bean时，一切都很好。我只需要添加另一个CommonJExecutor。