Question

我已经为此花了一段时间，现在我觉得事情已经太复杂了。我所拥有的是包含字段的表

OpenDate
ClosedDate
客户
合同
服务

我需要把它变成

日期
客户
合同
服务
OpenedOnThisDay
昨天开放
今天关闭
昨天关闭
OpenAtStartOfTomorrow
OpenAtStartOfToday

对于任何给定的日期，当天可能没有打开或关闭任何问题。该天仍应包含0's

我采用了多种方法，可以一次产生一个期望的结果（打开，关闭，结束时打开），但是我无法一次全部获得它们，至少不能成倍地增加增加查询时间。

我当前作为视图的查询如下

打开

select Cast(EntryDateTime as Date) as DateStamp
  ,ContractNumber
  ,Client
  ,services.Service
  ,sum(1) as Count
  ,lag(sum(1)) OVER (
    partition by tickets.ContractNumber
    ,services.Service ORDER BY Cast(EntryDateTime as Date) ASC
    ) as CountDayBefore
from v_JiraImpactedServices as services
LEFT JOIN v_JiraTickets as tickets ON services.ticketnumber = tickets.TicketNumber
WHERE tickets.Client is not null
  AND tickets.TicketNumber IS NOT NULL
  and tickets.ContractNumber is not null
GROUP BY Cast(tickets.EntryDateTime as Date)
  ,tickets.ContractNumber
  ,tickets.Client
  ,services.Service;

关闭日期

select Cast(ResolvedDateTime as Date) as DateStamp
  ,ContractNumber
  ,Client
  ,services.Service
  ,sum(1) as Count
  ,lag(sum(1)) OVER (
    partition by tickets.ContractNumber
    ,services.Service ORDER BY Cast(ResolvedDateTime as Date) ASC
    ) as CountDayBefore
from v_JiraImpactedServices as services
LEFT JOIN v_JiraTickets as tickets ON services.ticketnumber = tickets.TicketNumber
WHERE tickets.Client is not null
  and tickets.TicketNumber is not null
  AND tickets.ContractNumber is not null
GROUP BY Cast(tickets.ResolvedDateTime as Date)
  ,tickets.ContractNumber
  ,tickets.Client
  ,services.Service;

打开

SELECT calendar.FullDate as DateStamp
  ,tickets.ContractNumber
  ,tickets.client
  ,services.Service
  ,IsNull(count(tickets.TicketNumber), 0) as Count
  ,IsNull(lag(count(tickets.TicketNumber), 1) OVER (
      partition by tickets.ContractNumber
      ,services.Service Order By FullDate ASC
      ), 0) as CountDayBefore
FROM v_Calendar as calendar
LEFT JOIN v_JiraTickets as tickets ON Cast(tickets.EntryDateTime as Date) <= calendar.FullDate
  AND (
    Cast(tickets.ResolvedDateTime as Date) > calendar.FullDate
    OR tickets.ResolvedDateTime is null
    )
LEFT JOIN v_JiraImpactedServices as services ON services.ticketnumber = tickets.TicketNumber
WHERE tickets.Client is not null
  AND tickets.ContractNumber is not null
GROUP BY calendar.FullDate
  ,tickets.ContractNumber
  ,tickets.Client
  ,services.Service;

正如我所说的那样，它们本身都能给ALMOST带来理想的结果，但是省略了0值的日子。

除了生成具有0个值的天数外，我还需要将这些值合并为一个表结果。到目前为止，所有尝试要么产生明显错误的JOIN结果，要么执行一个小时。

如果有人能指出我正确的方向，我将不胜感激。

Answer 1

只是给您一个想法，尽管字段名称与您的情况不符，但这是我的处理方式：

apply plugin: 'com.android.application'

android {
buildToolsVersion '28.0.2'
compileSdkVersion 28

dexOptions {
    javaMaxHeapSize "4g"
}
defaultConfig {
    applicationId "xxxxxxxxxxxxxxxxxx"
    minSdkVersion 15
    targetSdkVersion 28
    // Enabling multidex support.
    multiDexEnabled true
}
sourceSets {
    main {
        manifest.srcFile 'AndroidManifest.xml'
        java.srcDirs = ['src']
        aidl.srcDirs = ['src']
        renderscript.srcDirs = ['src']
        res.srcDirs = ['res']
        assets.srcDirs = ['assets']
        jniLibs.srcDirs = ['libs']
    }

    androidTest.setRoot('tests')
}
}


repositories {
    mavenCentral()
    google()
    jcenter()
}

dependencies {
api project(':BaseGameUtils')
api files('libs/AudienceNetwork.jar')
api files('libs/FacebookAdapter.jar')
implementation files('libs/chartboost.jar')
implementation files('libs/chartboost-7.2.0.1.aar')
api 'com.android.support:multidex:1.0.3'

api 'com.facebook.android:facebook-android-sdk:4.36.1'

api 'com.google.firebase:firebase-core:16.0.1'
api 'com.google.firebase:firebase-analytics:16.0.1'
api 'com.google.firebase:firebase-invites:16.0.1'
api 'com.google.firebase:firebase-ads:15.0.1'
api 'com.google.firebase:firebase-messaging:17.1.0'
api 'com.google.firebase:firebase-appindexing:16.0.1'
api 'com.google.android.gms:play-services-analytics:16.0.1'
api 'com.google.android.gms:play-services-games:15.0.1'
api 'com.google.android.gms:play-services-identity:15.0.1'
api 'com.google.android.gms:play-services-plus:15.0.1'
}

查询给定日期的未解决问题的运行统计

1 个答案: