Question

所以我试图做一个简单的程序，但是我的Insert出现错误，我也不知道为什么。我已经创建了序列和表（Lab1_tab），但此处未包括它们。入学表和学生表都可以正常工作。我的错误是在第18行的第一个插入上。确切的错误是PLS-00103：遇到符号“ INSERT”

DECLARE
v_lname VARCHAR(20);
v_id NUMBER(3);
BEGIN
  SELECT s.last_name
  INTO v_lname
  FROM enrollment e, student s
  WHERE e.student_id = s.student_id
  AND LENGTH(s.last_name) < 9
  GROUP BY s.last_name
  HAVING COUNT(*) = ( SELECT MAX(count(student_id))
            FROM enrollment
            GROUP BY student_id);
EXCEPTION
  WHEN TOO_MANY_ROWS THEN
    v_lname := 'Multiple Names';
END;
INSERT INTO Lab1_tab                        //ERROR
   VALUES(LAB1_SEQ.NEXTVAL, v_lname);
BEGIN
      SELECT s.last_name
      INTO v_lname
      FROM enrollment e, student s
      WHERE e.student_id = s.student_id
      AND LENGTH(s.last_name) < 9
      GROUP BY s.last_name
      having count(*) = ( SELECT MIN(count(student_id))
                        FROM enrollment
                        GROUP BY student_id);
    EXCEPTION 
      WHEN TOO_MANY_ROWS THEN
        v_lname := 'Multiple Names';
    END;
    INSERT INTO Lab1_tab
       VALUES (LAB1_SEQ.NEXTVAL, v_lname);
BEGIN
      SELECT i.last_name
      INTO v_lname
      FROM instructor i, section s
      WHERE s.instructor_id = i.instructor_id
      AND i.last_name NOT LIKE '%s'
      GROUP BY i.last_name
      having count(*) = ( SELECT MIN(count(*))
                        FROM section
                        GROUP BY instructor_id );
    EXCEPTION 
      WHEN TOO_MANY_ROWS THEN
        v_lname := 'Multiple Names';
    END;
    INSERT INTO Lab1_tab
      VALUES (1, v_lname); 
BEGIN
    SELECT i.last_name
    INTO v_lname
    FROM instructor i, section s
    WHERE s.instructor_id = i.instructor_id
    AND i.last_name NOT LIKE '%s'
    GROUP BY i.last_name
    having count(*) = ( SELECT MAX(count(*))
                        FROM section
                        GROUP BY instructor_id );
EXCEPTION 
  WHEN TOO_MANY_ROWS THEN
    v_lname := 'Multiple Names';
END;
INSERT INTO Lab1_tab
    VALUES (LAB1_SEQ.NEXTVAL, v_lname);  
END;
/

Answer 1

看来，您正在尝试执行PL / SQL匿名块，但是很快就关闭了该块。即第一个END，您可能打算关闭“ try-catch”块，实际上关闭了整个容器。
也许您对DECLARE感到困惑，该BEGIN正在启动匿名块，但不是开始一个代码块-您仍然必须拥有DECLARE v_lname VARCHAR(20); v_id NUMBER(3); BEGIN BEGIN SELECT s.last_name INTO v_lname FROM enrollment e, student s WHERE e.student_id = s.student_id AND LENGTH(s.last_name) < 9 GROUP BY s.last_name HAVING COUNT(*) = ( SELECT MAX(count(student_id)) FROM enrollment GROUP BY student_id); EXCEPTION WHEN TOO_MANY_ROWS THEN v_lname := 'Multiple Names'; END; INSERT INTO Lab1_tab //ERROR VALUES(LAB1_SEQ.NEXTVAL, v_lname); BEGIN SELECT s.last_name INTO v_lname FROM enrollment e, student s WHERE e.student_id = s.student_id AND LENGTH(s.last_name) < 9 GROUP BY s.last_name having count(*) = ( SELECT MIN(count(student_id)) FROM enrollment GROUP BY student_id); EXCEPTION WHEN TOO_MANY_ROWS THEN v_lname := 'Multiple Names'; END; INSERT INTO Lab1_tab VALUES (LAB1_SEQ.NEXTVAL, v_lname); BEGIN SELECT i.last_name INTO v_lname FROM instructor i, section s WHERE s.instructor_id = i.instructor_id AND i.last_name NOT LIKE '%s' GROUP BY i.last_name having count(*) = ( SELECT MIN(count(*)) FROM section GROUP BY instructor_id ); EXCEPTION WHEN TOO_MANY_ROWS THEN v_lname := 'Multiple Names'; END; INSERT INTO Lab1_tab VALUES (1, v_lname); BEGIN SELECT i.last_name INTO v_lname FROM instructor i, section s WHERE s.instructor_id = i.instructor_id AND i.last_name NOT LIKE '%s' GROUP BY i.last_name having count(*) = ( SELECT MAX(count(*)) FROM section GROUP BY instructor_id ); EXCEPTION WHEN TOO_MANY_ROWS THEN v_lname := 'Multiple Names'; END; INSERT INTO Lab1_tab VALUES (LAB1_SEQ.NEXTVAL, v_lname); END; /。
尝试这样的事情：

BEGIN

修改：
总而言之，如果有疑问，请计算您的END和{{1}}并查看数字是否匹配。：）

Answer 2

在PL / SQL匿名阻止之后，需要有一个/字符才能运行DDL语句。

PL / SQL错误：遇到符号“ INSERT”

2 个答案: