我正在开发一个带有登录屏幕的简单应用程序。在我的视图控制器(LoginViewController)的代码中,我创建了以下函数,该函数应允许用户注册。但是,当我测试应用程序时,控制台会告诉我“由于格式不正确,无法读取数据。”
@IBAction func onSignUp(_ sender: Any) {
let newUser = PFUser()
newUser.username = usernameField.text as String!
newUser.password = passwordField.text as String!
newUser.signUpInBackground { (success: Bool, error: Error?) in
if success {
print("Created User")
} else {
print(error!.localizedDescription)
}
}
}
我怀疑即时通讯遇到某种类型的错误?文本字段是否需要字符串以外的其他数据类型?知道为什么会这样吗?有任何已知的解决方案吗?
答案 0 :(得分:0)
这两行很奇怪:
[[UNUserNotificationCenter currentNotificationCenter] setDelegate:self];
UNUserNotificationCenter *center = [UNUserNotificationCenter currentNotificationCenter];
UNAuthorizationOptions options = UNAuthorizationOptionAlert + UNAuthorizationOptionSound;
// Request using shared Notification Center
[center requestAuthorizationWithOptions:options
completionHandler:^(BOOL granted, NSError * _Nullable error) {
if (granted) {
NSLog(@"Notification Granted");
}
}];
// Notification authorization settings
[center getNotificationSettingsWithCompletionHandler:^(UNNotificationSettings * _Nonnull settings) {
if (settings.authorizationStatus == UNAuthorizationStatusAuthorized) {
NSLog(@"Notification allowed");
}
}];
UNMutableNotificationContent *content = [UNMutableNotificationContent new];
content.title = title;
content.body = body;
content.sound = [UNNotificationSound defaultSound];
NSDate *date = [NSDate date];
// Trigger with date
NSDateComponents *triggerDate = [[NSCalendar currentCalendar]
components:NSCalendarUnitYear +
NSCalendarUnitMonth + NSCalendarUnitDay +
NSCalendarUnitHour + NSCalendarUnitMinute +
NSCalendarUnitSecond fromDate:date];
UNCalendarNotificationTrigger *trigger = [UNCalendarNotificationTrigger triggerWithDateMatchingComponents:triggerDate
repeats:NO];
// Scheduling the notification
UNNotificationRequest *request = [UNNotificationRequest requestWithIdentifier:@"Identifier" content:content trigger:trigger];
[center addNotificationRequest:request withCompletionHandler:^(NSError * _Nullable error) {
if (error != nil) {
NSLog(@"Something went wrong: %@",error);
}
}];
PFUser上的newUser.username = usernameField.text as String!
newUser.password = passwordField.text as String!
和username
变量是否隐式地解开了可选变量?即使那样,我们通常也不会在Swift中编写这样的代码。我们可能会按照以下方式写一些东西:
password
尝试