使用Orientdb 3和tinkerpop 3识别2个顶点是否与边连接

时间:2018-09-20 15:01:32

标签: orientdb tinkerpop orientdb-etl

我一直在尝试浏览文档。我只是想找到一个简单的示例,以便将2个顶点相互连接时进行标识(如标题中所述)。这适用于使用tinkerpop API蓝图2.6的OrientDB 3。 例如:     顶点v1;     顶点v2;

boolean connected = false;

connected = <somefunction returns true/false if v1 and v2 connected by an edge>;

如果有人看到过这样的东西,可以请提供一个例子吗?

2 个答案:

答案 0 :(得分:1)

尝试一下:

String db_name = "dbname";
String path = "remote:localhost/" + db_name;

OrientDB orientDB = new OrientDB("remote:localhost", "username", "password", OrientDBConfig.defaultConfig());

try(ODatabaseSession db = orientDB.open(db_name,"username","password")) 
{
    ORID theEdge = new ORecordId("edge_rid");
    OEdge e = db.load(theEdge);

    ORID theVertex = new ORecordId("v1_rid");
    OVertex v1 = db.load(theVertex);

    ORID theVertex2 = new ORecordId("v2_rid");
    OVertex v2 = db.load(theVertex2);

    boolean connected = false;
    OVertex from = e.getFrom();
    OVertex to = e.getTo();

    if(from.getIdentity().equals(v1) && to.getIdentity().equals(v2))
    {
        connected = true;
    }

    if(connected)
    {
        System.out.println("Vertex v1: " + from.getIdentity());
        System.out.println("Vertex v2: " + to.getIdentity());
    }
}



希望对您有帮助

致谢

答案 1 :(得分:0)

您需要迭代一个顶点(v1)的边缘,并检查其是否连接到另一顶点(v2):

OrientVertex v1,v2; 
for (Edge e : (Iterable<Edge>)() ->  v1.edges(Direction.OUT)) 
    if (e.vertices(Direction.IN).next().id().equals(v2.id())) {
    }