我在HomeScreen.js中有一个组件LatestAdded.js,当按下它时,我想导航到另一个名为ProductDetailScreen.js的屏幕,但是当HomeScreen.js呈现时,我遇到了一个问题,它直接导航到ProductDetailScreen.js,并且如果我按下后退按钮并导航到HomeScreen.js,然后按下LatestAdded.js组件,则会显示错误true不是函数(评估this.props.viewdetail())
LastedAdded.js
<TouchableWithoutFeedback onPress={() => {
this.props.viewdetail();
}}>
<View style={{
flex: 1,
flexDirection: 'row',
borderRadius: 4,
borderWidth: 0.5,
borderColor: '#d6d7da', width: 180, padding: 5, marginRight: 5, height: 120
}}>
<View style={{}}>
<Text style={{ fontSize: 15, marginTop: 20 }}> {this.props.title}</Text>
<Text style={{ fontSize: 15, fontWeight: '700', marginTop: 10, marginBottom:10 }}> {this.props.author}</Text>
<StarRating
disabled={false}
maxStars={5}
starSize= {10}
rating={3}
fullStarColor= '#EDC430'
selectedStar={(rating) => this.onStarRatingPress(rating)}
/>
</View>
<Image style={{ width: 80, height: 100, margin: 2 }} source={{ uri: this.props.image }} />
</View>
</TouchableWithoutFeedback>
在HomeScreen.js中渲染methon
renderItem = ({ item }) => {
return (
<LatestAdded title={item.pro_name} author={item.pro_price} image={item.img_path}
viewdetail = { this.props.navigation.navigate('ProductDetail',{pro:item.pro_id})} />
)}
ProductDetailScreen.js
class ProductDetailScreen extends Component {
render() {
const { navigation } = this.props;
const itemId = navigation.getParam('pro', 'none');
return (
<View style={styles.container}>
<Text>{itemId}</Text>
</View>
);
}
}
答案 0 :(得分:0)
您的问题在这里:
posts: [Post!]!
您想传递一个函数以便稍后调用,但是您可以立即调用该函数
尝试以下方法:
viewdetail = { this.props.navigation.navigate('ProductDetail',{pro:item.pro_id})}