我正在使用array_filter
搜索并删除不需要的结果,我英语不好,这是我的做法:
$obj_Data = [
[
"id" => 1,
"level" => "admin",
"name" => "jack"
],
[
"id" => 2,
"level" => "member",
"name" => "john"
],
[
"id" => 3,
"level" => "member",
"name" => "jenny"
],
[
"id" => 4,
"level" => "member",
"name" => "whatever"
]
];
function filter_callback($element) {
if ($element["level"] == "member") {
return TRUE;
}
return FALSE;
}
$arr["data"] = array_filter($obj_Data, "filter_callback");
echo json_encode($arr);
它给我的结果是:
{
"data": {
"1": {
"id": 2,
"level": "member",
"name": "john"
},
"3": {
"id": 4,
"level": "member",
"name": "whatever"
}
}
}
这是我想要的结果:
{
"data": {
{
"id": 2,
"level": "member",
"name": "john"
},
{
"id": 4,
"level": "member",
"name": "whatever"
}
}
}
如何删除“ 1”和“ 3”?因为感谢您的阅读,我无法使用循环。
答案 0 :(得分:2)
array_filter()
保留使用的数组键,使结果数组成为JSON上下文中的对象。只需在通过JSON编码之前通过array_values()
重新索引数组即可。