Question

我正在处理的项目是使用实体过滤支持的JHipster生成的，该过滤器在后台使用了Spring Data JPA规范。

模型如下（在JDL中）：

entity Student {
    name String
}

entity Course {
    name String
}

entity Enrollment {
}

entity Attendance {
    date LocalDate
}

relationship OneToMany {
    Student to Enrollment(student required),
    Course to Enrollment(course required),
    Enrollment to Attendance(enrollment required)
}

filter all
service all with serviceClass

JHipster生成了用于通过Attendance过滤enrollmentId的样板，但是我想扩展它使其能够被studentId和courseId过滤。

因此，我该如何实现一个规范来执行类似以下的查询：

SELECT
  attendance.date, student.name as student, course.name as course
FROM attendance
JOIN enrollment
  ON enrollment.id = attendance.enrollment_id
JOIN student
  ON student.id = enrollment.student_id
  AND studend.id = 1
JOIN course
  ON course.id = enrollment.course_id
  AND course.id = 2;

Answer 1

根据@GaëlMarziou的建议，我已经实现了一些简单的方法来创建Specification<Attendance>与Student和Course联接。

我将字段，获取器和设置器添加到AttendanceCriteria类中，并重新编译以更新JPA元模型：

private LongFilter studentId;

private LongFilter courseId;

public LongFilter getStudentId() {
    return studentId;
}

public void setStudentId(LongFilter studentId) {
    this.studentId = studentId;
}

public LongFilter getCourseId() {
    return courseId;
}

public void setCourseId(LongFilter courseId) {
    this.courseId = courseId;
}

这是AttencanceQueryService类的最新摘录：

private Specification<Attendance> createSpecification(AttendanceCriteria criteria) {
    Specification<Attendance> specification = Specification.where(null);
    if (criteria != null) {
        if (criteria.getId() != null) {
            specification = specification.and(buildSpecification(criteria.getId(), Attendance_.id));
        }
        if (criteria.getDate() != null) {
            specification = specification.and(buildRangeSpecification(criteria.getDate(), Attendance_.date));
        }
        if (criteria.getEnrollmentId() != null) {
            specification = specification.and(buildReferringEntitySpecification(criteria.getEnrollmentId(), Attendance_.enrollment, Enrollment_.id));
        }
        if (criteria.getStudentId() != null) {
            specification = specification.and(buildJoinSpecification(criteria.getStudentId(), Attendance_.enrollment, Enrollment_.student, Student_.id));
        }
        if (criteria.getCourseId() != null) {
            specification = specification.and(buildJoinSpecification(criteria.getCourseId(), Attendance_.enrollment, Enrollment_.course, Course_.id));
        }
    }
    return specification;
}

private <REFERENCE, JOIN, FILTER extends Comparable<? super FILTER>> Specification<Attendance> buildJoinSpecification(RangeFilter<FILTER> filter, SingularAttribute<? super Attendance, REFERENCE> reference, SingularAttribute<REFERENCE, JOIN> joinField, SingularAttribute<JOIN, FILTER> valueField) {
    Specification<Attendance> result = Specification.where((Specification) null);
    if (filter.getEquals() != null) {
        result = this.equalsSpecification(reference, joinField, valueField, filter.getEquals());
    }
    if (filter.getIn() != null) {
        result = this.valueIn((SingularAttribute) reference, joinField, valueField, filter.getIn());
    }
    return result;
}

private <REFERENCE, JOIN, FILTER> Specification<Attendance> equalsSpecification(SingularAttribute<? super Attendance, REFERENCE> reference, SingularAttribute<REFERENCE, JOIN> joinField, SingularAttribute<JOIN, FILTER> idField, FILTER value) {
    return (root, query, builder) ->
        builder.equal(root.join(reference).join(joinField).get(idField), value);
}

private <REFERENCE, JOIN, FILTER> Specification<Attendance> valueIn(SingularAttribute<? super Attendance, REFERENCE> reference, SingularAttribute<REFERENCE, JOIN> joinField, SingularAttribute<JOIN, FILTER> valueField, Collection<FILTER> values) {
    return (root, query, builder) -> {
        CriteriaBuilder.In<FILTER> in = builder.in(root.join(reference).join(joinField).get(valueField));
        for (FILTER value : values) {
            in = in.value(value);
        }
        return in;
    };
}

我希望这对某人有帮助，功劳归功于@GaëlMarziou和Blackdread/Yoann Caplain。

如何编写具有多个联接的Spring Data JPA规范？

1 个答案: