我想从poll
表中选择行,并按已连接vote
表中vote.is_current_vote = true
的行数或行总数对它们进行排序。
“投票”表会跟踪所有投票,但是在投票中只记录每位用户的最新投票,投票标记为is_current_vote
。
我正在努力研究如何使用“ Doctrine查询生成器”或“本机查询”来获取Vote表的计数。
这是数据库结构:
create table if not exists user
(
id int auto_increment
primary key,
username varchar(45) not null,
slug varchar(45) not null,
created_at datetime not null,
updated_at datetime null,
constraint UNIQ_8D93D649989D9B62
unique (slug),
constraint UNIQ_8D93D649F85E0677
unique (username)
)
collate=utf8_unicode_ci
;
create table if not exists poll
(
id int auto_increment
primary key,
user_id int null,
question varchar(140) not null,
slug varchar(140) not null,
is_active tinyint(1) not null,
created_at datetime not null,
updated_at datetime null,
constraint UNIQ_84BCFA45989D9B62
unique (slug),
constraint FK_84BCFA45A76ED395
foreign key (user_id) references user (id)
)
collate=utf8_unicode_ci
;
create index IDX_84BCFA45A76ED395
on poll (user_id)
;
create table if not exists vote
(
id int auto_increment
primary key,
poll_id int not null,
user_id int not null,
created_at datetime not null,
is_current_vote tinyint(1) not null,
constraint FK_5A1085643C947C0F
foreign key (poll_id) references poll (id),
constraint FK_5A108564A76ED395
foreign key (user_id) references user (id),
)
collate=utf8_unicode_ci
;
create index IDX_5A1085643C947C0F
on vote (poll_id)
;
create index IDX_5A108564A76ED395
on vote (user_id)
;
我在MySQL中运行此查询,这为我提供了我想要的数据:
select poll.id, poll.slug, poll.question, poll.created_at,
u.id, u.username, u.slug, u.profile_picture,
sum(case when v.is_current_vote = true then 1 else 0 end) as total_votes
from poll
left join user u on poll.user_id = u.id
left join vote v on poll.id = v.poll_id
group by poll.id
order by total_votes desc
数据应按“ v.is_current_vote = true”的票数排序。
示例数据(省略了上面的某些列,因此更易于阅读):
poll.question, u.username, total_votes
Is Elvis Alive?, someone, 15
Is the future bright?, someone_else, 10
Is this all a dream?, another_user, 5
是否可以在Symfony / Doctrine QueryBuilder语句中执行类似的操作,还是必须使用本机SQL?我也无法解决该怎么做。非常感谢您提供一些指导。
这是我当前的本机SQL尝试,我从poll
表中获得行,但表决和用户均为null
:
/**
* Class PollRepository
* @package PollBundle\Repository
*/
class PollRepository extends EntityRepository
{
/**
* @return \Doctrine\ORM\NativeQuery
*/
public function findPopular()
{
$rsm = new ResultSetMappingBuilder($this->_em);
$rsm->addRootEntityFromClassMetadata('PollBundle\Entity\Poll', 'poll');
$rsm->addJoinedEntityFromClassMetadata('PollBundle\Entity\User', 'u', 'poll', 'user', [
'id' => 'user_id',
'slug' => 'user_slug',
'created_at' => 'user_created_at',
'updated_at' => 'user_updated_at',
'is_active' => 'user_is_active',
]);
$rsm->addJoinedEntityFromClassMetadata('PollBundle\Entity\Vote', 'v', 'poll', 'votes', [
'id' => 'vote_id',
'user_id' => 'vote_user_id',
'created_at' => 'vote_created_at',
'updated_at' => 'vote_updated_at',
]);
$sql = '
SELECT poll.id, poll.slug, poll.question, poll.created_at,
u.id, u.username, u.slug, u.profile_picture,
sum(case when v.is_current_vote = true then 1 else 0 end) as total_votes
from poll
left join user u on poll.user_id = u.id
left join vote v on poll.id = v.poll_id
group by poll.id
order by total_votes desc
';
return $this->_em->createNativeQuery($sql, $rsm)->getResult();
}
}
答案 0 :(得分:1)
您是否尝试过与此查询类似的内容? Doctrine几乎可以完成SQL的所有工作。
$query = $this->createQueryBuilder('p')
->select('p.question, u.username, count(v.isCurrentVote) AS votes')
// joins maybe need change depending on your relations
->leftJoin('p.user', 'u')
->leftJoin('p.votes', 'v')
->groupBy('p.id')
->orderBy('votes');
return $query->getQuery()->getResult();