当我在JavaScript中使用PHP时，所有脚本都不起作用... 即使我在评论中使用php。
<script></script>上面的注释破坏了<?php
session_start();
if (isset($_POST['login']) && isset($_POST['password']) && isset($_POST['email']))
{
$validation = true;
$firstName = $_SESSION['firstName'];
$lastName = $_SESSION['lastName'];
$street = $_SESSION['street'];
$phone = $_SESSION['phone'];
$login = $_POST['login'];
$password = $_POST['password'];
$email = $_POST['email'];
require_once "connect.php";
mysqli_report(MYSQLI_REPORT_STRICT);
try
{
$connection = new mysqli($host, $db_user, $db_password, $db_name);
if($connection->connect_errno!=0)
{
throw new Exception(mysqli_connect_errno());
}
else
{
if ($validation == true) // when validation process will be successfuly done - i cut validation process
{
if($connection->query("INSERT INTO users values (NULL, '$firstName', '$lastName', '$street', '$phone', '$login', '$password', '$email')"))
{
$_SESSION['abc'] = "done";
//here is also header(location) to login page
}
else
{
throw new Exception($connection->error);
}
}
$connection->close();
}
}
catch(Exception $e)
{
echo '<div class="error">error. sorry, please to register in other term</div>';
}
}
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8" />
<script>
//there are other functions for local/session storage
function deleteSessionData()
{
var variable = "<?php echo $_SESSION['abc']; ?>";
if(variable == "done")
{
sessionStorage.removeItem('firstName');
sessionStorage.removeItem('lastName');
sessionStorage.removeItem('street');
sessionStorage.removeItem('phone');
sessionStorage.removeItem('login');
sessionStorage.removeItem('password');
sessionStorage.removeItem('email');
}
}
</script>
</head>
<body>
<form id="myForm" method="post">
<label for="login">Login: </label>
<input type="text" id="login" name="login">
<label for="password">Password: </label>
<input type="text" id="password" name="password">
<label for="email">E-mail:</label>
<input type="email" id="email" name="email">
<button onclick="java script: document.getElementById('myForm').submit();deleteSessionData();">Register</button>
</form>
</div>
</body>
</html>
标签中的所有脚本。
当我删除带有注释的这一行时，每个脚本都将起作用。
同样的事情是当我只想在JavaScript中使用PHP（不带注释）时。
你能帮我吗？
这是我截断的代码（仅向您提供代码的必要部分），请帮助:)：
@Query("INSERT INTO TestTable VALUES(null,:a,:b)")
List<TestTable> getall(String a, String b, String columna, String columnb);
答案 0 :(得分：1)
您也需要注释php
//var variable = <?php // echo json_encode($_SESSION['abc']); ?>;
但是，如果没有卫生条件，我不会将PHP注入这样的javascript中。