Question

所以我在这里有这么长的查询：

showings = db.execute("SELECT showings.cinema_id, showings.movie_id,\
                       cinemas.name, movies.name FROM showings JOIN\
                       cinemas ON showings.cinema_id=cinemas.id JOIN\
                       movies ON showings.movie_id=movies.id WHERE\
                       showings.id = :id", 
                      {"id": cinema_id}).fetchall()
return render_template("showings.html", showings2=showings2)

，然后在模板中：

{% for showing in showings2 %}
   <option value="{{ showing.id }}">
     {{ showing.name }} @{{ showing.name }}
   </option>
{% endfor %}

问题是由于两个不同表中的列名相同，当前模板两次返回相同的内容，即Cinema.name的值是否可以绕过它？

Answer 1

使用别名重命名列：

showings = db.execute(
    """SELECT showings.cinema_id
            , showings.movie_id
            , cinemas.name AS cinema_name
            , movies.name AS movie_name
       FROM   showings 
       JOIN   cinemas ON showings.cinema_id=cinemas.id
       JOIN   movies ON showings.movie_id=movies.id
       WHERE  showings.id = :id""", {"id": cinema_id}).fetchall()

并在模板中使用上述别名：

<option value="{{ showing.id }}">
    {{ showing.cinema_name }} @ {{ showing.movie_name }}
</option>

从flask-sqlalchemy中的联接查询中读取列名

1 个答案: