我有一个包含另一个类对象的请求类。现在,我想将嵌套的JSON解析为“请求类对象”。
我正在尝试使用ObjectMapper
,但抛出异常。请帮助我使用Java Jackson 。
{
"filters":[
{
"key":"CustomerId",
"op":"=",
"value" : "1"
},
{
"key":"userName",
"op":"=",
"value" : "admin"
}
],
"startIndex" : 1,
"size" : 10,
"OrderBy" :
{
"propertyId" : "userName",
"Desc" : false
},
"TimeRange" : {
"startTimestamp" : 1,
"endTimestamp" :10
}
}
逻辑:
public static class OrderBy {
private String propertyId;
private boolean desc = true;
}
class TimeRange {
private Long startTimestamp;
private Long endTimestamp;
}
class Filter {
private String propertyId;
private String op;
private Object value;
}
public class Request {
private List<Filter> filters;
private TimeRange timeRange;
private OrderBy orderBy;
private int startIndex = 0;
private int size = 20;
}
答案 0 :(得分:0)
我给你一个Jaskson Util Tools类。
package com.jackson.utils;
import com.fasterxml.jackson.core.type.TypeReference;
import com.fasterxml.jackson.databind.ObjectMapper;
/**
* The class JacksonUtil
*
* json字符与对像转换
*
* @version: $Revision$ $Date$ $LastChangedBy$
*
*/
public final class JacksonUtil {
public static ObjectMapper objectMapper;
/**
* 使用泛型方法,把json字符串转换为相应的JavaBean对象。
* (1)转换为普通JavaBean:readValue(json,Student.class)
* (2)转换为List,如List<Student>,将第二个参数传递为Student
* [].class.然后使用Arrays.asList();方法把得到的数组转换为特定类型的List
*
* @param jsonStr
* @param valueType
* @return
*/
public static <T> T readValue(String jsonStr, Class<T> valueType) {
if (objectMapper == null) {
objectMapper = new ObjectMapper();
}
try {
return objectMapper.readValue(jsonStr, valueType);
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
/**
* json数组转List
* @param jsonStr
* @param valueTypeRef
* @return
*/
public static <T> T readValue(String jsonStr, TypeReference<T> valueTypeRef){
if (objectMapper == null) {
objectMapper = new ObjectMapper();
}
try {
return objectMapper.readValue(jsonStr, valueTypeRef);
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
/**
* 把JavaBean转换为json字符串
*
* @param object
* @return
*/
public static String toJSon(Object object) {
if (objectMapper == null) {
objectMapper = new ObjectMapper();
}
try {
return objectMapper.writeValueAsString(object);
} catch (Exception e) {
e.printStackTrace();
}
return null;
}
}
现在,您可以使用隐藏代码秘密请求:
String userBeanToJson = "your json string";//please replace this for your need json
Request jsonToUserBean = JacksonUtil.readValue(userBeanToJson, Request.class);
希望对您有用。