Question

我创建了3个组件。 1）登录屏幕2）VenueList屏幕3）菜单屏幕我创建了另一个名为AuthLoading的组件，该组件将用户从登录屏幕导航到VenueList屏幕。 AuthLoading是连接登录前组件和登录后组件的桥梁组件。

登录屏幕上有一个按钮，onclick将触发loginAction.js，并且用户被导航到Web浏览器，在此他输入电子邮件/密码。收到accessToken后，必须将用户导航到VenueList屏幕，但switchNavigator不起作用。我该如何实施？

Login.js：

import React, { Component } from 'react';
import { Button, StyleSheet, View } from 'react-native';
import { connect } from 'react-redux';
import { loginUser } from '../actions/loginAction';

class Login extends Component {

  _signInAsync = async () => {
    await AsyncStorage.setItem('accessToken', this.props.accessToken);
    this.props.navigation.navigate('App');
  }

  render() {

    console.log(this.props.accessToken);

    return (
      <View style={styles.container}>
        <Button
        onPress={this.props.loginUser}
        title="Click to Login"
        ></Button>
      </View>
    );
  }

}

loginAction.js：

import { LOGIN_USER } from './types';
import Auth0 from 'react-native-auth0';

var credentials = require('./auth0-credentials');
const auth0 = new Auth0(credentials);

export const loginUser = () => dispatch => {

    auth0.webAuth
    .authorize({
      scope: 'openid profile',
      audience: 'https://' + credentials.domain + '/userinfo'
    })
    .then(credentials => 

        dispatch({
            type: LOGIN_USER,
            payload: credentials.accessToken
        })
    )
    .catch(error => console.log(error));

};

authLoading.js：

import React, { Component } from 'react';
import { StyleSheet, View, ActivityIndicator, AsyncStorage, StatusBar } from 'react-native';

export default class AuthLoading extends Component {

  constructor() {
    super();
    this._bootstrapAsync();
  }

  _bootstrapAsync = async () => {
    const accessToken = await AsyncStorage.getItem('accessToken');

    // This will switch to the App screen or Auth screen and this loading
    // screen will be unmounted and thrown away.
    this.props.navigation.navigate(accessToken ? 'App' : 'Auth');
  };

  render() {

    return (
        <View style={styles.container}>
            <ActivityIndicator />
            <StatusBar barStyle="default" />
        </View>
    );
  }

}

app.js：

const AppStack = createStackNavigator({ Venues: VenueList, Menu: ItemsMenu });
const AuthStack = createStackNavigator({ Login: Login });

const AppStackNavigator = createSwitchNavigator(
  {
    AuthLoading: AuthLoadingScreen,
    App: AppStack,
    Auth: AuthStack,
  },
  {
    initialRouteName: 'AuthLoading',
  }
);

屏幕截图：

在上面的屏幕截图中，在收到accessToken之后，用户再次导航回登录屏幕，但我不想将用户导航到VenueList屏幕。

Answer 1

您可以检查accessToken组件中的渲染功能开始时是否设置了Login，并在登录后将用户导航到VenueList屏幕。

class Login extends Component {

  _signInAsync = async () => {
    await AsyncStorage.setItem('accessToken', this.props.accessToken);
    this.props.navigation.navigate('App');
  }

  render() {
    if(this.props.accessToken) {
      this.props.navigation.navigate('VenueList')
    }

    return (
      <View style={styles.container}>
        <Button
        onPress={this.props.loginUser}
        title="Click to Login"
        ></Button>
      </View>
    );
  }

}

Answer 2

您不应在渲染中导航。在componentDidMount()或componetDidUpdate()

中进行操作

class Login extends Component {

  _signInAsync = async () => {
    await AsyncStorage.setItem('accessToken', this.props.accessToken);
    this.props.navigation.navigate('App');
  }

  componentDidMount(){
    if(this.props.accessToken) {
      this.props.navigation.navigate('VenueList')
    }
  }

  render() {

    return (
      <View style={styles.container}>
        <Button
        onPress={this.props.loginUser}
        title="Click to Login"
        ></Button>
      </View>
    );
  }

}

如何使用反应导航在屏幕之间切换？

2 个答案: