如何使用mysql内部联接计数其他表中的行数？

Question

我有以下3张桌子：

crm_customers：

crm_progress：

crm_notifications：

我想要以下结果：

要实现上述要求的输出，我正在使用以下查询：

SELECT `cc`.`customer_id`, `cc`.`customer_name`, COUNT(`cp`.`progress_customer`) AS Progress, COUNT(`cn`.`notification_customer`) AS Notifications 
FROM `crm_customers` AS `cc` INNER JOIN `crm_progress` AS `cp` 
ON `cc`.`customer_id` = `cp`.`progress_customer` 
INNER JOIN `crm_notifications` AS `cn` 
ON `cn`.`notification_customer` = `cp`.`progress_customer` 
WHERE `cc`.`customer_id` = 1 AND `cc`.`customer_status` = 1 

但是结果出来是完全错误的。但是，当我仅连接2个表时，结果是准确的。

以下查询带来正确的输出：

SELECT `cc`.`customer_id`, `cc`.`customer_name`, COUNT(`cp`.`progress_customer`) AS Progress 
FROM `crm_customers` AS `cc` INNER JOIN `crm_progress` AS `cp` 
ON `cc`.`customer_id` = `cp`.`progress_customer` 
WHERE `cc`.`customer_id` = 1 AND `cc`.`customer_status` = 1

我在哪里做错了？如何正确使用联接来获取所需的结果？

Answer 1

请尝试以下查询：您需要计算与某些客户相关联的progress_id和notification_id

SELECT `cc`.`customer_id`, `cc`.`customer_name`, COUNT(distinct `cp`.`progress_id`) AS Progress, COUNT(distinct `cn`.`notification_id`) AS Notifications 
FROM `crm_customers` AS `cc` INNER JOIN `crm_progress` AS `cp` 
ON `cc`.`customer_id` = `cp`.`progress_customer` 
INNER JOIN `crm_notifications` AS `cn` 
ON `cn`.`notification_customer` = `cp`.`progress_customer` 
WHERE `cc`.`customer_id` = 1 AND `cc`.`customer_status` = 1 
group by `cc`.`customer_id`, `cc`.`customer_name`

Answer 2

可以使用以下查询来实现：

var complaintsData