Question

我正在尝试使用express测试简单的API请求-响应。但是，请求必须在请求对象中包含以下字段： user.userName和user.password，这是我到目前为止的代码：

const express = require('express');
const log = require('../../../../logger');
const app = express();
const ClusterNode = require('../cluster-node');

// TODO: don't like these here. Needed to post. Put into global test startup if possible.
// TODO - OMRI: Reaplce this with the global test startup, when created.
const socketio = require('socket.io');
app.io = socketio.listen();
const bodyParser = require('body-parser');
app.use(bodyParser.json());


app.use('/v2/config/aw/', ClusterNode);
app.use(function(req, res, next) {
  req.user.userName = 'xxxx';
  req.user.password = 'xxxx';
  next();
});

describe('API - ClusterNode', () => {
  test('API - Get Cluster Nodes #1', () => {
    return request(app).get('/v2/config/aw/ClusterNode').then((response) => {
      expect(response.statusCode).toBe(200);
      expect(response.body.Node.length.toString()).toBe('0');
      expect(response.headers['content-type']).toMatch(/^application\/json/);
    });
  });
});

我尝试添加以下代码块：

app.use(function(req, res, next) {
  req.user.userName = 'xxxx';
  req.user.password = 'xxxx';
  next();
});

但是它没有完成这项工作。任何想法如何做到这一点？预先感谢。

Answer 1

您的用于设置userName和password的中间件函数是在路由处理程序之后声明的，所以我猜测它没有被调用。在声明路线之前将其移动，例如

app.use(function(req, res, next) {
  req.user = {
    'userName': 'xxxx',
    'password': 'xxxx'
  };
  next();
});
app.use('/v2/config/aw/', ClusterNode);

Answer 2

如果要在req.user中使用用户对象，请使用：

app.use(function(req, res, next) {
 req.user = {
   'userName': 'xxxx',
   'password': 'xxxx'
 };
next();
});
app.use('/v2/config/aw/', ClusterNode);

，如果您希望它包含在req.body中，请使用：

app.use(function(req, res, next) {
 req.body.user = {
   'userName': 'xxxx',
   'password': 'xxxx'
 };
next();
});
app.use('/v2/config/aw/', ClusterNode);

修改测试API请求-响应时Express发送的请求对象

2 个答案: