Question

我有一个具有很多属性的模型，我想将该模型编码为url查询参数。

public typealias Parameters = [String : Any]

enum ProductWriteApi {
   case addOFFProduct(product: OFFProduct)
}

extension ProductWriteApi: EndPointType {
   var parameters: Parameters {
    switch self {
    case .addOFFProduct(let product):
        var parameters: Parameters!
        do {
            //Need to encode the product model to be like the Example parameters down there.
            let data = try JSONEncoder().encode(product)
            //This data wont be sent in the body. It will be sent in the URL.
        } catch {

        }
        //Example parameters needed
        parameters = [
            "name": "Cereal",
            "categorie": "Milks"
        ]

        return parameters
    }
  }
}

因此，我如何才能将产品模型更改/编码为[String : Any]，以便能够遍历它们并将其添加到我的url字符串中。还是我必须逐个传递每个产品属性，然后检查它是否不是nil也不为空并将其添加到[String : Any]类型的变量中？

还是有我不知道的另一种更简单的解决方案？

这是一个静态函数，它通过遍历参数并将其附加到查询项中来将参数添加到我的url中。

public struct URLParameterEncoder: ParameterEncoder {

 public static func encode(urlRequest: inout URLRequest, with parameters: Parameters) throws {
    guard let url = urlRequest.url else { throw NetworkError.missingURL}

    if var urlComponents = URLComponents(url: url, resolvingAgainstBaseURL: false) {
        urlComponents.queryItems = [URLQueryItem]()

        for (key,value) in parameters {
            let queryItem = URLQueryItem(name: key, value: "\(value)".addingPercentEncoding(withAllowedCharacters: .urlHostAllowed))
            urlComponents.queryItems?.append(queryItem)
        }

        urlRequest.url = urlComponents.url
    }

    if urlRequest.value(forHTTPHeaderField: "Content-Type") == nil {
        urlRequest.setValue("application/x-www-form-urlencoded; charset=utf-8", forHTTPHeaderField: "Content-Type")
    }
 }

}

将模型属性编码为查询URL参数

0 个答案: