Question

请求您的帮助以使用XSLT 2转换XML

我的输入XML如下所示。

    <?xml version="1.0" encoding="UTF-8"?>
<Workers>
    <Worker>
        <Batch_number>1234</Batch_number>
        <Name>David</Name>
        <Assignment>
            <type>A</type>
            <name>New York</name>
        </Assignment>
    </Worker>
    <Worker>
        <Batch_number>1234</Batch_number>
        <Name>David</Name>
        <Assignment>
            <type>B</type>
            <name>Boston</name>
        </Assignment>
    </Worker>
    <Worker>
        <Batch_number>1234</Batch_number>
        <Name>David</Name>
        <Assignment>
            <type>C</type>
            <name>Chicago</name>
        </Assignment>
    </Worker>
    <Worker>
        <Batch_number>78698</Batch_number>
        <Name>Karen</Name>
        <Assignment>
            <type>C</type>
            <name>Chicago</name>
        </Assignment>
    </Worker>
</Workers>

所需的输出如下所示。

<?xml version="1.0" encoding="UTF-8"?>
<Worker>
    <Batch_number>1234</Batch_number>
    <Name>David</Name>
    <Assignment>
            <type>A</type>
            <name>New York</name>
        </Assignment>
    <Assignment>
            <type>B</type>
            <name>Boston</name>
        </Assignment>
    <Assignment>
            <type>C</type>
            <name>Chicago</name>
        </Assignment>
</Worker>
<Worker>
    <Batch_number>78698</Batch_number>
    <Name>Karen</Name>
    <Assignment>
            <type>C</type>
            <name>Chicago</name>
        </Assignment>
</Worker>

转换的条件是：

如果输入文件中存在具有相同<Worker>的子节点<Batch_number>，则应将同一Assignment的所有<Batch_number>节点归为一个Worker子节点在<Batch_number>和<Name>之后

有人可以帮助我编写正确的代码来实现这一目标吗？

-谢谢阿努普

Answer 1

尽管所需的输出XML格式不正确，但是这里有一个XSLT-2.0解决方案可以满足您的特殊需求：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" indent="yes"/>

    <xsl:template match="/Workers">
        <xsl:for-each-group select="Worker" group-by="Batch_number">
            <Worker>
                <Batch_number><xsl:value-of select="current-grouping-key()" /></Batch_number>
                <Name><xsl:value-of select="current()/Name" /></Name>
                <xsl:copy-of select="current-group()/Assignment" />
            </Worker>
        </xsl:for-each-group>
    </xsl:template>

</xsl:stylesheet>

其输出为：

<?xml version="1.0" encoding="UTF-8"?>
<Worker>
    <Batch_number>1234</Batch_number>
    <Name>David</Name>
    <Assignment>
        <type>A</type>
        <name>New York</name>
    </Assignment>
    <Assignment>
        <type>B</type>
        <name>Boston</name>
    </Assignment>
    <Assignment>
        <type>C</type>
        <name>Chicago</name>
    </Assignment>
</Worker>
<Worker>
    <Batch_number>78698</Batch_number>
    <Name>Karen</Name>
    <Assignment>
        <type>C</type>
        <name>Chicago</name>
    </Assignment>
</Worker>

XSLT中的条件分组

1 个答案: