运行此代码时,它将生成适当的文件上载ui,并将事件侦听器添加到上载按钮。但是,上载函数的第一行为此this.missingFile引发错误-无法读取未定义的属性'style'。我在这里做什么错了?
function FileUploader(props) {
var div = document.querySelector(props.element);
var uid = generateGuid();
var templateHtml = "<p><div id=\"dvMissingFile-" + uid + "\" class=\"missing-file\"> Please choose a file.</div><input type=\"file\" id=\"flUploadedFile-" + uid + "\" name=\"flUploadedFile-" + uid + "\"/></p><div class=\"dvProgressBar\" id=\"progress-" + uid + "\"><div></div></div>";
div.innerHTML = templateHtml;
this.uploadButton = document.querySelector(props.uploadButton);
this.fileInput = document.querySelector("#flUploadedFile-" + uid);
this.missingFile = document.querySelector("#dvMissingFile-" + uid);
this.progress = document.querySelector("#progress-" + uid);
this.url = props.postUrl;
this.upload = function() {
this.missingFile.style.display = "none";
if (this.fileInput.files.length === 0) {
this.missingFile.style.display = "";
}
else {
var file = this.fileInput.files[0];
var xhr = new XMLHttpRequest();
var pbar = document.querySelector("#progress-" + uid + ">div");
if (xhr.upload) {
// do upload
}
}
}
this.uploadButton.addEventListener("click", this.upload);
}
用法示例
<div id="dvUploader"></div>
<button type="button" id="btnUpload" class="btn btn-primary">Upload</button>
<script>
var uploader = new FileUploader({
element: "#dvUploader",
uploadButton: "#btnUpload",
postUrl: "myposturl"
});
</script>
答案 0 :(得分:1)
对代码进行一次小的更新可以帮助:
this.upload = function() {
// ...
}.bind(this);