我有如下表格。
Workid StartDate EndDate
101 2012-03-01 2013-03-20
101 2013-03-21 2014-08-01
102 2014-01-01 2014-12-31
103 2012-01-01 2012-10-11
103 2012-10-12 2014-12-31
104 2012-01-01 2012-12-25
105 2012-01-01 2014-06-30
105 2014-07-01 2014-12-31
我需要验证给定年份的工作量是否已完全占用。例如，如果我将年份选择为2012，则输出应如下所示。
WorkID STATUS
101 Not Occupied
102 Not Occupied
103 Occupied
104 Not Occupied
105 Occupied
如果将年份选择为2013，则输出应如下所示。
WorkID STATUS
101 Occupied
102 Not Occupied
103 Occupied
104 Not Occupied
105 Occupied
有人可以帮忙吗？
下面是示例表脚本。
CREATE TABLE #temp
(
Workid INT,
StartDate DATE,
EndDate DATE
)
go
INSERT INTO #temp
(
Workid,
StartDate,
EndDate
)
VALUES
(101, '2012-03-01', '2013-03-20'),
(101, '2013-03-21', '2014-08-01'),
(102, '2014-01-01', '2014-12-31'),
(103, '2012-01-01', '2012-10-11'),
(103, '2012-10-12', '2014-12-31'),
(104, '2012-01-01', '2012-12-25'),
(105, '2012-01-01', '2014-06-30'),
(105, '2014-07-01', '2014-12-31')
;
答案 0 :(得分：0)
使用以下查询
select b.WORKID, (case when b.SD_COUNT > 0 and b.ED_COUNT > 0 then 'Occupied' else 'Not Occupied' end ) as STATUS from
(select a.Workid as WORKID, Sum(a.Status_StartDate) as SD_COUNT, Sum(a.Status_EndDate) as ED_COUNT from
(Select Workid, (case when StartDate <= '2012-01-01' then 1 else 0 end as Status_StartDate), (case when EndDate >= '2012-12-31' then 1 else 0 end) as Status_EndDate from tablename)a group by a.Workid)b;
答案 1 :(得分：0)
您首先需要确定每个WorkId的最小StartDate和最大EndDate：
SELECT [WorkId]
, MIN([StartDate]) AS [StartDate]
, MAX([EndDate]) AS [EndDate]
FROM [#temp]
GROUP BY [WorkId]
通过一些日期操作，您需要弄清楚要评估的年份的开始日期和结束日期，例如：
DECLARE @Year INT = 2012;
DECLARE @YearBegin DATE;
DECLARE @YearEnd date;
SET @YearBegin = DATEADD(yy, @Year - 1900, 0);
SET @YearEnd = DATEADD(DAY, -1, DATEADD(yy, 1, @YearBegin));
SELECT @YearBegin
, @YearEnd;
然后，我们可以根据@YearBegin和@yearEnd评估开始日期和结束日期，以确定“已完全占用”。
这是假设每个ID的数据范围之间没有间隙：
DECLARE @Year INT = 2012;
DECLARE @YearBegin DATE;
DECLARE @YearEnd DATE;
SET @YearBegin = DATEADD(yy, @Year - 1900, 0);
SET @YearEnd = DATEADD(DAY, -1, DATEADD(yy, 1, @YearBegin));
SELECT [WorkId]
, CASE WHEN [fr].[StartDate] <= @YearBegin
AND [fr].[EndDate] >= @YearEnd THEN 'Occupied'
ELSE 'Not Occupied'
END AS [Status]
FROM (
SELECT [WorkId]
, MIN([StartDate]) AS [StartDate]
, MAX([EndDate]) AS [EndDate]
FROM [#temp]
GROUP BY [WorkId]
) AS [fr];
如果每个ID的日期范围和/或日期范围之间可能存在间隙，则以下是递归CTE的示例，该示例可以解决这些情况：
DECLARE @Year INT = 2013
, @TotalDayYear INT;
--For the year we are evalutaing, how many days total in that year
--We'll use for comparison later
SET @TotalDayYear = DATEDIFF(
DAY
, CONCAT(@Year - 1, '-12-31')
, CONCAT(@Year, '-12-31')
);
DECLARE @YearOccupied TABLE
(
[WorkId] INT
, [YearOccupied] INT
, [CountDaysOccupied] INT
);
--Recursive CTE to get list of every day a particular ID occupied based on the date ranges.
WITH [Cte]
AS ( SELECT [WorkId]
, [StartDate]
, [EndDate]
, [StartDate] AS [DateOccupied]
FROM [#temp]
UNION ALL
SELECT [a].[WorkId]
, [a].[StartDate]
, [a].[EndDate]
, DATEADD(DAY, 1, [b].[DateOccupied]) AS [DateOccupied]
FROM [#temp] [a]
INNER JOIN [Cte] [b]
ON [b].[WorkId] = [a].[WorkId]
AND [b].[StartDate] = [a].[StartDate]
AND [b].[EndDate] = [a].[EndDate]
AND [b].[DateOccupied] < [a].[EndDate] )
--We'll insert into a table variable a count by year for each Id
INSERT INTO @YearOccupied (
[WorkId]
, [YearOccupied]
, [CountDaysOccupied]
)
SELECT [do].[WorkId]
, YEAR([DateOccupied]) AS [YearOccupied]
, COUNT(*) AS [DaysOccupiedCount]
FROM (
--Use a sub-query here to get a distinct Date Occupied
--To account for overlapping data ranges
SELECT DISTINCT [WorkId]
, [DateOccupied]
FROM [Cte]
) AS [do]
GROUP BY [do].[WorkId]
, YEAR([DateOccupied])
OPTION ( MAXRECURSION 0 );
SELECT [a].[WorkId]
, @Year AS [YearOccupied]
--Coaleace as we may have a year an ID didn't occupy at all
--compared to the total days of the year to determine fully occupied or not
, CASE WHEN COALESCE([b].[CountDaysOccupied], 0) = @TotalDayYear THEN
'Occupied'
ELSE 'Not Occupied'
END AS [Status]
FROM (
--We could have a year we want data for that a particular id didn't occupy.
--We'll build a distinct list of ID and our evalution year for doing a left outer to
--accually see if the year was occupied.
SELECT DISTINCT [WorkId]
, @Year AS [YearOccupied]
FROM @YearOccupied
) AS [a]
LEFT OUTER JOIN @YearOccupied [b]
ON [b].[WorkId] = [a].[WorkId]
AND [b].[YearOccupied] = @Year;
答案 2 :(得分：0)
这花了我一段时间，但查询仍然有效。可能有更好的方法，但是正如我所说，这确实有效。测试一下，祝你好运！
USE tempdb
DECLARE @StartDate DATE
DECLARE @EindDate DATE
SET @StartDate = '1990-01-01' -- << user input >> --
SET @EindDate = '2018-12-31' -- << user input >> --
IF OBJECT_ID ('TEMPDB..#Date') IS NOT NULL DROP TABLE #Date
IF OBJECT_ID ('TEMPDB..#Date') IS NULL CREATE TABLE #Date (Date_ DATE)
INSERT INTO #Date VALUES (@StartDate)
WHILE @StartDate < @EindDate
BEGIN
INSERT INTO #Date
SELECT DATEADD (DD, 1, @StartDate) AS Date
SET @StartDate = DATEADD (DD, 1, @StartDate)
END;
SELECT * FROM #Date
CREATE TABLE #temp
(
Workid INT,
StartDate DATE,
EndDate DATE
)
GO
INSERT INTO #temp
(
Workid,
StartDate,
EndDate
)
VALUES
(101, '2012-03-01', '2013-03-20'),
(101, '2013-03-21', '2014-08-01'),
(102, '2014-01-01', '2014-12-31'),
(103, '2012-01-01', '2012-10-11'),
(103, '2012-10-12', '2014-12-31'),
(104, '2012-01-01', '2012-12-25'),
(105, '2012-01-01', '2014-06-30'),
(105, '2014-07-01', '2014-12-31');
CREATE TABLE #WorkID (WorkID INT)
INSERT INTO #WorkID VALUES (101), (102), (103), (104), (105)
CREATE TABLE #Yrs (Yrs INT)
INSERT INTO #Yrs VALUES (2012), (2013), (2014)
SELECT *
INTO #ResultSet
FROM #WorkID
CROSS JOIN #Yrs;
WITH CTE AS
(
SELECT Workid, YEAR (Date_) AS Yr, COUNT(*) AS WorkedDays
FROM #Date AS D
INNER JOIN #temp AS T ON D.Date_ >= T.StartDate AND D.Date_ <= T.EndDate
GROUP BY Workid, YEAR (Date_)
)
SELECT R.WorkID,
Yrs AS Year_,
CASE WHEN Yr % 4 = 0 AND WorkedDays = 366 THEN 'Occupied'
WHEN Yr % 4 <> 0 AND WorkedDays = 365 THEN 'Occupied'
ELSE 'Not Occupied'
END AS OccupiedStatus
FROM #ResultSet AS R
LEFT JOIN CTE AS C ON C.Workid = R.WorkID AND Yrs = Yr
ORDER BY 2, 1
答案 3 :(得分：0)
您可以使用递归cte来找到每个工作ID的日期范围并进行比较，这也可以解决工作中的差距（演示：http://rextester.com/NUEW6510）
DECLARE @year INT = 2013;
WITH calendarSearch (Workid,StartDate, EndDate, StartDate2, EndDate2) AS
(
SELECT Workid,StartDate, EndDate, CAST('1900-01-01' AS DATE), CAST('1900-01-01' AS DATE)
FROM #temp
UNION ALL
SELECT c.Workid, c.StartDate, t.EndDate, t.StartDate, c.EndDate
FROM #temp t
JOIN calendarSearch c
ON c.Workid = t.Workid
AND t.EndDate > c.EndDate
AND t.StartDate <= DATEADD(DAY,1,c.EndDate)
), occupiedRange AS
(
SELECT Workid,StartDate, EndDate FROM calendarSearch c
WHERE c.StartDate NOT IN (SELECT StartDate2 FROM calendarSearch WHERE calendarSearch.Workid = c.Workid)
AND c.EndDate NOT IN (SELECT EndDate2 FROM calendarSearch WHERE calendarSearch.Workid = c.Workid)
)
SELECT Workid,
CASE WHEN EXISTS (SELECT 1 FROM occupiedRange WHERE Workid = o1.Workid and StartDate <= datefromparts(@year,1,1) AND EndDate >= DATEFROMPARTS(@year,12,31)) THEN 'Occupied' ELSE 'Not Occupied' END AS Status
FROM occupiedRange o1
GROUP BY o1.Workid
ORDER BY Workid