Question

继续我以前的question。

我有一个称为拒绝的文本日志文件。您可以看到它here

如您所见，选项卡上有四个步骤：

1. Battery level
2. Piezo sound level
3. Left D3  (Ch 3) light intensity
4. Right D2  (Ch 1) light intensity

现在，我想对每个带有条件的行进行计数：

Which column(Steps) value is filled then count it.
Example: on row 1, We can see the value 0 (any value) is on step Piezo sound level. Then count it.

所以最终我可以知道有多少数量的拒绝过程。

Battery level = x quantity
Piezo sound level = x quantity
Left D3  (Ch 3) light intensity = x quantity
Right D2  (Ch 1) light intensity = x quantity

PHP代码：

$fromDateTime = new DateTime('Wed, Sep 19  2018 08:00:00');
$toDateTime = new DateTime('Wed, Sep 19  2018 19:59:00');
$file = file_get_contents('reject.txt');
$lines = explode("\n",$file);

// counter
$rowsintimespan = 0;

// Do Line-By-Line starting by Line 16 (Array Index 15)
for($i = 15; $i < count($lines); $i++) {
// if the file is "Tue, Sep 18<tab>2018<tab>23:59:53<tab>"
$dateobj = DateTime::createFromFormat("???,?M?d??Y?H:i:s+", $lines[$i]);

// check if date is in your Timespan
if($dateobj < $toDateTime && $dateobj > $fromDateTime) {
        $rowsintimespan++; // count if in timespan
    }
}

// Debug-Output
echo $rowsintimespan;

更新

我需要读取最后一列的值，例如：如果该行的值在左D3列上，则对其进行计数。如果row的值在Piezo列上，则对其进行计数。

Answer 1

如果您可以将列记为键，则可以按照您的描述进行操作：

$fromDateTime = new DateTime('Wed, Sep 19  2018 08:00:00');
$toDateTime = new DateTime('Wed, Sep 19  2018 19:59:00');
$file = file_get_contents('Reject.txt');
$lines = explode("\n", $file);

// counter
$rowsintimespan = 0;
// keys should correspond to columns
$keys = [
    'date',
    'time',
    'battery',
    'piezo',
    'leftD3',
    'rightD2'
];

$values = array_fill(0, count($keys), 0);
$values = array_combine($keys, $values);

// Do Line-By-Line starting by Line 16 (Array Index 15)
for ($i = 11; $i < count($lines); $i++) {
    // if the file is "Tue, Sep 18<tab>2018<tab>23:59:53<tab>"
    $dateobj = DateTime::createFromFormat("???,?M?d??Y?H:i:s+", $lines[$i]);

    // check if date is in your Timespan
    if ($dateobj < $toDateTime && $dateobj > $fromDateTime) {
        $rowsintimespan++; // count if in timespan

        // get line elements
        $lineContent = explode("\t", $lines[$i]);

        // loop through line elements and count them
        $x = 0;
        for ($j = 0; $j < count($keys); $j++) {
            if (!isset($lineContent[$j])) {
                continue;
            }

            // remember position of last not empty column
            if (trim($lineContent[$j]) != '') {
                $x = $j;
            }
        }

        if ($x > 0) {
            $values[$keys[$x]]++;
        }
    }
}

// Debug-Output
echo $rowsintimespan;

// Output every column
echo '<pre>';
print_r($values);

这将打印出来：

Array
(
    [date] => 0
    [time] => 0
    [battery] => 4
    [piezo] => 31
    [leftD3] => 17
    [rightD2] => 1
)

Answer 2

只需按标签将行分开，然后检查！empty（）;

//Set Time-Span
$fromDateTime = new DateTime('Wed, Sep 19  2018 00:00:00');
$toDateTime = new DateTime('Wed, Sep 19  2018 17:00:00');

// Load File
$file = file_get_contents('Reject.txt');

// Split by lines
$lines = explode("\n",$file);

// counter
$rowsintimespan = 0;
$rowswithbattery = 0;

// Do Line-By-Line starting by Line 16 (Array Index 15)
for($i = 15; $i < count($lines); $i++) {
    // if the file is "Tue,<space>Sep<space>18<space><space>2018<tab>23:59:53<tab>"
    $dateobj = DateTime::createFromFormat("???, M  d?Y?H:i:s+", $lines[$i]);

    // check if date is in your Timespan
    if($dateobj < $toDateTime && $dateobj > $fromDateTime) {
        $rowsintimespan++; // count if in timespan
        $cols = explode("\t",$lines[$i]);
        // 0 = Date, 1 = Time, 2 = Battery Level, 3 = Piezo, 4 = left, 5 = Right
        // Count Battery-Values
        if (!empty($cols[2])) {
            $rowswithbattery++;
        }
    }
}

// Debug-Output
echo 'In Timespan: '.$rowsintimespan."\n";
echo 'Rows With Battery: '.$rowswithbattery

产生：

In Timespan: 84
Rows With Battery: 84

包含所有列的完整示例：https://ideone.com/VAQH7h

您还可以遍历每个标头并创建一个整齐的数组，如我在https://ideone.com/YUU1jP中所示

// Split by lines
$lines = explode("\n", $file);
$header = explode("\t", $lines[9]);
// counter
$rowsintimespan = 0;
$counter = Array();

// Create an entry for every header and trim it to lose additional whitespaces
foreach($header as $index => $head){
    $counter[rtrim($head)] = 0;
}

// Do Line-By-Line starting by Line 16 (Array Index 15)
for($i = 11; $i < count($lines); $i++) {
    // the file is "Tue,<space>Sep<space>18<space><space>2018<tab>23:59:53<tab>"
    $dateobj = DateTime::createFromFormat("???, M d  Y?H:i:s+", $lines[$i]);
    // check if date is in your Timespan
    if($dateobj < $toDateTime && $dateobj > $fromDateTime) {
        $rowsintimespan++; // count if in timespan
        $cols = explode("\t",$lines[$i]);
        // 0 = Date, 1 = Time, 2 = Battery Level, 3 = Piezo, 4 = left, 5 = Right
        // Count Battery-Values
        foreach($header as $index => $head){
            // For every header check if col is empty
            $counter[rtrim($head)] += empty($cols[$index]) ? 0 : 1;
        }
    }
}

// Debug-Output
echo 'In Timespan: '.$rowsintimespan."\n";
var_dump($counter);

更新以匹配更新的问题：

然后只需做一些简单的数学运算即可。

理论：如果您有80个带电池的固定列和20个带固定压电的列，则可以从80个电池计数器中减去20个压电计数器，然后知道多少个电池列和最后一个压电列

因此：

$lastwithright = $rowswithright;
$lastwithleft = $rowswithleft - $rowswithright;
$lastwithpiezo = $rowswithpiezo - $rowswithleft;
$lastwithbattery = $rowswithbattery - $rowswithpiezo;

PHP根据值列对文本文件上的行/行进行计数

2 个答案: