Question

在我的Django项目中，我必须从 forms 中获取输入并将其作为 views.py 中的函数的参数传递。我该怎么办？

我的views.py代码

from django.shortcuts import render,render_to_response
from django.http import Http404, HttpResponse, HttpResponseRedirect
from search_engine import query
from .forms import SearchForm


def query_input(request):
    if request.method == "POST":

        form = SearchForm(request.POST)

    else:
        form = SearchForm()
        return render(request, 'search.html', {'form': form})

def search_results(request):
    search_results = query.results(# text input from forms)
    a = "<br /><br />".join(word for word in search_results)
    return HttpResponse(a)

我的forms.py代码

from django import forms

class SearchForm(forms.Form):
    your_query = forms.CharField(max_length=100)

Answer 1

在检查request方法是POST之后，您可以验证表单，然后像这样访问其属性

在views.py中：

if request.method = "POST":
    form = SearchForm(request.POST)
    if form.is_valid():
        search_text = form.cleaned_data['search_text']
        # code from search_results function to return HTTP Response

请查看表单文档，并查看here以获取更多信息。

如何将表单“文本”输入传递给views.py中的另一个变量

1 个答案: