Question

我有一个来自links = set(soup.findAll('a'))的列表，现在我想对它们进行排序，但是links = sorted(links)出现错误，该怎么排序？

原始列表和其他所有属性：

<a href="//weathernews.jp/typhoon/">台風</a>
<a class="list" href="https://weathernews.jp/s/topics/201809/190035/?fm=tp_index"></a>
<a class="list" href="https://weathernews.jp/s/topics/201809/130155/?fm=tp_index"></a>
<a href="//weathernews.jp/warning/">警報・注意報</a>
<a class="list" href="https://weathernews.jp/s/topics/201809/140125/?fm=tp_index"></a>
<a class="list" href="https://weathernews.jp/s/topics/201809/170145/?fm=tp_index"></a>

我想对它进行排序

<a class="list" href="https://weathernews.jp/s/topics/201809/190035/?fm=tp_index"></a>
<a class="list" href="https://weathernews.jp/s/topics/201809/170145/?fm=tp_index"></a>
<a class="list" href="https://weathernews.jp/s/topics/201809/140125/?fm=tp_index"></a>
<a class="list" href="https://weathernews.jp/s/topics/201809/130155/?fm=tp_index"></a>
<a href="//weathernews.jp/typhoon/">台風</a>
<a href="//weathernews.jp/warning/">警報・注意報</a>

Answer 1

我建议您先将链接映射到字符串，然后对其进行排序。

links = set(soup.findAll('a'))
links = map(str, links)
links = sorted(links)

或

简单地

links = sorted(set(map(str, links)))

Answer 2

我明白了

links = sorted(links, key=lambda x: str(x), reverse=False)

Python对具有不同属性的标签进行排序

2 个答案: