我想通过代理发送电子邮件。
我目前的实施如下：
我通过身份验证连接到smtp服务器。我成功登录后，发送电子邮件。它工作正常，但当我看到电子邮件标题时，我可以看到我的主机名。我想通过代理隧道它。
任何帮助都将受到高度赞赏。
答案 0 :(得分：9)
使用SocksiPy：
import smtplib
import socks
#'proxy_port' should be an integer
#'PROXY_TYPE_SOCKS4' can be replaced to HTTP or PROXY_TYPE_SOCKS5
socks.setdefaultproxy(socks.PROXY_TYPE_SOCKS4, proxy_host, proxy_port)
socks.wrapmodule(smtplib)
smtp = smtplib.SMTP()
...
答案 1 :(得分：4)
昨天我遇到了类似的问题，这是我为解决问题所写的代码。它无形中允许您通过代理使用所有smtp方法。
#!/usr/bin/env python
# -*- coding: utf-8 -*-
#
# smtprox.py
# Shouts to suidrewt
#
# ############################################# #
# This module allows Proxy support in MailFux. #
# Shouts to Betrayed for telling me about #
# http CONNECT #
# ############################################# #
import smtplib
import socket
def recvline(sock):
stop = 0
line = ''
while True:
i = sock.recv(1)
if i == '\n': stop = 1
line += i
if stop == 1:
break
return line
class ProxSMTP( smtplib.SMTP ):
def __init__(self, host='', port=0, p_address='',p_port=0, local_hostname=None,
timeout=socket._GLOBAL_DEFAULT_TIMEOUT):
"""Initialize a new instance.
If specified, `host' is the name of the remote host to which to
connect. If specified, `port' specifies the port to which to connect.
By default, smtplib.SMTP_PORT is used. An SMTPConnectError is raised
if the specified `host' doesn't respond correctly. If specified,
`local_hostname` is used as the FQDN of the local host. By default,
the local hostname is found using socket.getfqdn().
"""
self.p_address = p_address
self.p_port = p_port
self.timeout = timeout
self.esmtp_features = {}
self.default_port = smtplib.SMTP_PORT
if host:
(code, msg) = self.connect(host, port)
if code != 220:
raise SMTPConnectError(code, msg)
if local_hostname is not None:
self.local_hostname = local_hostname
else:
# RFC 2821 says we should use the fqdn in the EHLO/HELO verb, and
# if that can't be calculated, that we should use a domain literal
# instead (essentially an encoded IP address like [A.B.C.D]).
fqdn = socket.getfqdn()
if '.' in fqdn:
self.local_hostname = fqdn
else:
# We can't find an fqdn hostname, so use a domain literal
addr = '127.0.0.1'
try:
addr = socket.gethostbyname(socket.gethostname())
except socket.gaierror:
pass
self.local_hostname = '[%s]' % addr
smtplib.SMTP.__init__(self)
def _get_socket(self, port, host, timeout):
# This makes it simpler for SMTP_SSL to use the SMTP connect code
# and just alter the socket connection bit.
if self.debuglevel > 0: print>>stderr, 'connect:', (host, port)
new_socket = socket.create_connection((self.p_address,self.p_port), timeout)
new_socket.sendall("CONNECT {0}:{1} HTTP/1.1\r\n\r\n".format(port,host))
for x in xrange(2): recvline(new_socket)
return new_socket
答案 2 :(得分：0)
此代码来自我。 1.文件名不能是email.py重命名文件名，例如emailSend.py 2.有必要允许Google从不可靠的来源发送消息。
答案 3 :(得分：0)
正如 mkerrig 和 Denis Cornehl 在对另一个答案的评论中指出的那样，PySocks create_connection 使用 smtplib 中的修改后的 SMTP 类可以工作，而无需为所有内容修改套接字。
我仍然讨厌这个实现（谁知道其他版本的 python 或 smtplib 会破坏什么），但它现在有效（3.8.1）。由于我无法在互联网上的其他地方找到任何其他有效的解决方案，这是我的尝试：
my_proxy_smtplib.py：
import socket
import smtplib
import socks
class ProxySMTP(smtplib.SMTP):
def __init__(self, host='', port=0, local_hostname=None,
timeout=socket._GLOBAL_DEFAULT_TIMEOUT,
source_address=None, proxy_addr=None, proxy_port=None):
"""Initialize a new instance.
If specified, `host' is the name of the remote host to which to
connect. If specified, `port' specifies the port to which to connect.
By default, smtplib.SMTP_PORT is used. If a host is specified the
connect method is called, and if it returns anything other than a
success code an SMTPConnectError is raised. If specified,
`local_hostname` is used as the FQDN of the local host in the HELO/EHLO
command. Otherwise, the local hostname is found using
socket.getfqdn(). The `source_address` parameter takes a 2-tuple (host,
port) for the socket to bind to as its source address before
connecting. If the host is '' and port is 0, the OS default behavior
will be used.
"""
self._host = host
self.timeout = timeout
self.esmtp_features = {}
self.command_encoding = 'ascii'
self.source_address = source_address
self.proxy_addr = proxy_addr
self.proxy_port = proxy_port
if host:
(code, msg) = self.connect(host, port)
if code != 220:
self.close()
raise smtplib.SMTPConnectError(code, msg)
if local_hostname is not None:
self.local_hostname = local_hostname
else:
# RFC 2821 says we should use the fqdn in the EHLO/HELO verb, and
# if that can't be calculated, that we should use a domain literal
# instead (essentially an encoded IP address like [A.B.C.D]).
fqdn = socket.getfqdn()
if '.' in fqdn:
self.local_hostname = fqdn
else:
# We can't find an fqdn hostname, so use a domain literal
addr = '127.0.0.1'
try:
addr = socket.gethostbyname(socket.gethostname())
except socket.gaierror:
pass
self.local_hostname = '[%s]' % addr
def _get_socket(self, host, port, timeout):
# This makes it simpler for SMTP_SSL to use the SMTP connect code
# and just alter the socket connection bit.
if self.debuglevel > 0:
self._print_debug('connect: to', (host, port), self.source_address)
return socks.create_connection((host, port),
proxy_type=socks.PROXY_TYPE_SOCKS5,
timeout=timeout,
proxy_addr=self.proxy_addr,
proxy_port=self.proxy_port)
并使用：
from my_proxy_smtplib import ProxySMTP
email_server = ProxySMTP('smtp.gmail.com', 587,
proxy_addr='192.168.0.1',
proxy_port=3487)
email_server.starttls()
email_server.login(user_email, user_pass)
email_server.sendmail(user_email, recipient_list, msg.as_string())
email_server.quit()
答案 4 :(得分：-1)
smtplib模块不包含通过HTTP代理连接到SMTP服务器的功能。 custom class posted by ryoh对我不起作用，显然是因为我的HTTP代理仅接收编码消息。我根据ryos的代码编写了以下自定义类，并且它工作正常。
import smtplib
import socket
def recvline(sock):
"""Receives a line."""
stop = 0
line = ''
while True:
i = sock.recv(1)
if i.decode('UTF-8') == '\n': stop = 1
line += i.decode('UTF-8')
if stop == 1:
print('Stop reached.')
break
print('Received line: %s' % line)
return line
class ProxySMTP(smtplib.SMTP):
"""Connects to a SMTP server through a HTTP proxy."""
def __init__(self, host='', port=0, p_address='',p_port=0, local_hostname=None,
timeout=socket._GLOBAL_DEFAULT_TIMEOUT):
"""Initialize a new instance.
If specified, `host' is the name of the remote host to which to
connect. If specified, `port' specifies the port to which to connect.
By default, smtplib.SMTP_PORT is used. An SMTPConnectError is raised
if the specified `host' doesn't respond correctly. If specified,
`local_hostname` is used as the FQDN of the local host. By default,
the local hostname is found using socket.getfqdn().
"""
self.p_address = p_address
self.p_port = p_port
self.timeout = timeout
self.esmtp_features = {}
self.default_port = smtplib.SMTP_PORT
if host:
(code, msg) = self.connect(host, port)
if code != 220:
raise IOError(code, msg)
if local_hostname is not None:
self.local_hostname = local_hostname
else:
# RFC 2821 says we should use the fqdn in the EHLO/HELO verb, and
# if that can't be calculated, that we should use a domain literal
# instead (essentially an encoded IP address like [A.B.C.D]).
fqdn = socket.getfqdn()
if '.' in fqdn:
self.local_hostname = fqdn
else:
# We can't find an fqdn hostname, so use a domain literal
addr = '127.0.0.1'
try:
addr = socket.gethostbyname(socket.gethostname())
except socket.gaierror:
pass
self.local_hostname = '[%s]' % addr
smtplib.SMTP.__init__(self)
def _get_socket(self, port, host, timeout):
# This makes it simpler for SMTP to use the SMTP connect code
# and just alter the socket connection bit.
print('Will connect to:', (host, port))
print('Connect to proxy.')
new_socket = socket.create_connection((self.p_address,self.p_port), timeout)
s = "CONNECT %s:%s HTTP/1.1\r\n\r\n" % (port,host)
s = s.encode('UTF-8')
new_socket.sendall(s)
print('Sent CONNECT. Receiving lines.')
for x in range(2): recvline(new_socket)
print('Connected.')
return new_socket
要连接到SMTP服务器，只需使用课程ProxySMTP代替smtplib.SMTP。
proxy_host = YOUR_PROXY_HOST
proxy_port = YOUR_PROXY_PORT
# Both port 25 and 587 work for SMTP
conn = ProxySMTP(host='smtp.gmail.com', port=587,
p_address=proxy_host, p_port=proxy_port)
conn.ehlo()
conn.starttls()
conn.ehlo()
r, d = conn.login(YOUR_EMAIL_ADDRESS, YOUR_PASSWORD)
print('Login reply: %s' % r)
sender = 'from@fromdomain.com'
receivers = ['to@todomain.com']
message = """From: From Person <from@fromdomain.com>
To: To Person <to@todomain.com>
Subject: SMTP e-mail test
This is a test e-mail message.
"""
print('Send email.')
conn.sendmail(sender, receivers, message)
print('Success.')
conn.close()