Question

所以我要在要求我确定年龄的地方进行这项练习以天为单位的某人基于其出生日期和当前日期的输入。例如（2012,1,1,2012,2,28）应该返回58 （也不允许我使用任何内置的时间函数）。到目前为止，这是我的代码：

def leapyear(year):
    return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)

def daysBetweenDates(year1, month1, day1, year2, month2, day2):
  age = 0
  months31 = [1,3,5,7,8,10,12]
  months30 = [4,6,9,11]
  while year1 != year2 and month1 != month2 and day1 != day2:
    age += day2
    day2 = 0
    if day2 == 0:
      month2-=1
      if month2 in months31:
        day2 += 31
        month2 -= 1
      if month2 in months30:
        day2 += 30
        month2 -= 1
      if month2 == 2:
        if leapyear(year2):
          day2 += 29
          month2 -= 1
        else:
          day2 += 28
          month2 -= 1
      else: 
        year2 -= 1
        month2 = 12     
  return age

无论如何，我的问题是，每当我尝试使用此函数时，它始终返回0，对此解决问题的任何帮助都将受到赞赏。

编辑：大家好，所以根据您的反馈，我了解了为什么我的代码要花很长时间才能运行，所以我将其更改为现在的样子：

def leapyear(year):
    return year % 4 == 0 and (year % 100 != 0 or year % 400 == 0)

def daysBetweenDates(year1, month1, day1, year2, month2, day2):
  # Your code here.
  age = 0
  months31 = [1,3,5,7,8,10,12]
  months30 = [4,6,9,11]
  if day1 != day2:
    age = abs(day2-day1)
    day2 = day1

  if month1 > month2:
    while month1 !=  month2:
      if month2 in months31:
        age += 31
        month2 += 1
      if month2 in months30:
        age += 30
        month2 += 1
      if month2 == 2:
        if leapyear(year2):
          age += 29
          month2 += 1
        else:
          age += 28
          month2 += 1
  else:
    while month1 !=  month2:
      if month2 in months31:
        age += 31
        month2 -= 1
      if month2 in months30:
        age += 30
        month2 -= 1
      if month2 == 2:
        if leapyear(year2):
          age += 29
          month2 -= 1
        else:
          age += 28
          month2 -= 1
  while year1 != year2:
    if leapyear(year2):
      age += 365
      year2 -= 1
    else:
      age += 365
      year2 -= 1

  return age

但是唯一的问题是，对于某些示例，它正在起作用，而对于其他示例，我正在接近答案，但不是确切的答案。例如，对于print(daysBetweenDates(2012, 1, 1, 2012, 2, 28))，我在56岁时应该得到58。

Answer 1

全无！一天，但这是您可以用来计算此过程的更好方法。第一次计算时发生了一些错误，现在运行非常棒！享受:)

def leap_year(y):
    if y % 4 == 0 and (y % 100 != 0 or year % 400 == 0):
        return True
    return False

def year_to_date(yeah, month, day):
    days = 0
    days += day
    for i in range(0, month - 1):
        if i == 1:
            if leap_year(year):
                days += 28
            else:
                days += 29 
        else:
            days += days_in_month[i]
    return days

def birth_to_new_year(year, month, day):
    days = 0
    days += days_in_month[month - 1] - day
    for i in range(month, 12):
        if i == 1:
            if leap_year(year):
                days += 28
            else:
                days += 29
        else:
            days += days_in_month[i]
    return days

days_in_month = [31, 0, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]

day = 18 
month = 9 
year = 2018 

birth_day = 20
birth_month = 11
birth_year = 1988

days = 0

for i in range(birth_year + 1, year):
    if leap_year(i):
        days += 366
    else:
        days += 365

days += year_to_date(year, month, day)
days += birth_to_new_year(birth_year, birth_month, birth_day)

print(days)

根据出生日期和当前日期输入某人的年龄

1 个答案: