将英寸转换为英尺，米和英里，不带小数

Question

我需要编写一个程序，要求用户提供英寸的总数，并将其值转换为英里，码，英尺和英寸。提示您的用户输入的整数英寸数。您可能会假设他们行为举止良好，并且可以按照说明进行操作，因此请务必为他们提供有关其数量多少的指导。转换它们的值并输出相应的英里数，码数，英尺和英寸，并在输出中标记每个值。例如，如果用户输入

158,430英寸，您的输出应类似于：

     158430 inches corresponds to:

                    2 miles

                    880 yards

                   2 feet

                   6 inches

对于相同的输入值，可能会认为您的输出是正确的，

     158430 inches corresponds to:

                    2 miles

                    880 yards

                   1 feet

                   18 inches

---

这是我到目前为止所拥有的

#include <stdio.h>

int main(void) {
float inches;
    printf("enter number of inches: ");
    scanf("%f", &inches);

    printf("value in miles is %f", inches/ 63360);
    printf("\nvalue in yards is %f", inches/36);
    printf("\nvalue in feet is %f", inches/12);
    printf("\nvalue in inches is %f", inches);

    return 0;
 }

Answer 1

这里没有语法问题。只是逻辑错误。计算单个英里，英尺，英寸，码的方法很好。但是以公制单位的降序查找剩余的方法有点不合逻辑。在计算了以英里，码等为单位的每个值之后，您需要计算还剩下多少英寸。

这是更新的代码：

#include <stdio.h>
 int main(void)
 {
 int inches;
 int miles, yards, feet;
      printf("enter number of inches: ");
     scanf("%d", &inches);
     //calculate miles and then find remaining inches
     miles = inches/ 63360;
     inches = inches - miles*63360;
     //calculate remaining yards and then remaining inches
     yards = inches/ 36;
     inches = inches - yards*36;
     //calculate feet and remaining inches after that
     feet = inches/ 12;
     inches = inches - feet*12;
     printf("%d inches corresponds to: ");
     printf("\n%d miles", miles);
     printf("\n%d yards", yards);
     printf("\n%d feet", feet);
     printf("\n%d inches", inches);

     return 0;
 }