我有一个名为name的字符串,我想在句子中的单词之间修剪空格,并在逗号后也修剪空格。
我可以在句子的开头和结尾使用trim()修剪多余的空格。
[我正在使用javascript来实现我的代码]
name = ' Barack Hussein Obama II is an American politician who served as the 44th President of the United States from January 20, 2009, to January 20, 2017.
预期输出:
name = ' Barack Hussein Obama II is an American politician who served as the 44th President of the United States from January 20, 2009, to January 20, 2017.
答案 0 :(得分:6)
假定其余的双空格只是一个错字,则可以使用正则表达式匹配一个或多个空格,并用一个空格替换每个空格:
const name1 = ' Barack Hussein Obama II is an American politician who served as the 44th President of the United States from January 20, 2009, to January 20, 2017.';
console.log(
name1.replace(/ +/g, ' ')
);
答案 1 :(得分:2)
在angularjs中,您可以使用trim()
函数
const nameStr = ' Barack Hussein Obama II is an American politician who served as the 44th President of the United States from January 20, 2009, to January 20, 2017.';
console.log(nameStr.replace(/\s+/g, ' ').trim());
答案 2 :(得分:2)
let msg = ' Barack Hussein Obama II is an American politician who served as the 44th President of the United States from January 20, 2009, to January 20, 2017.';
console.log(msg.replace(/\s\s+/g, ' '));
答案 3 :(得分:2)
默认情况下,JavaScript中的string.replace只会替换它找到的第一个匹配值,添加/ g表示将替换所有匹配值。
g正则表达式修饰符(称为全局修饰符)基本上告诉引擎在第一次匹配后不要停止解析字符串。
var string = " Barack Hussein Obama II is an American politician who served as the 44th President of the United States from January 20, 2009, to January 20, 2017."
alert(string)
string = string.replace(/ +/g, ' ');
alert(string)
有用的修饰符列表:
您可以将g和i等修饰词组合在一起,以进行不区分大小写的全局搜索。