我想上传一个文件并通过它传递模型。但是当我从邮递员那里尝试时,总是会出错。
这是我的代码
public async Task<IHttpActionResult> PostArPumPd([FromBody] tx_arPumPd pum)
{
try
{
if (pum == null)
{
return Content(HttpStatusCode.BadRequest, "Enter the data correctly");
}
else
{
tx_arPumPd arpumpds = new tx_arPumPd()
{
doc_no = doc,
doc_date = DateTime.Now,
descs = pum.descs,
currency_code = pum.currency_code,
amount = pum.amount,
employee_code = pum.employee_code,
head_code = pum.head_code,
company_code = pum.company_code,
created_by = pum.emp_code,
created_date = DateTime.Now
};
db.tx_arPumPd.Add(arpumpds);
var multiFormDataStreamProvider = new MultiFileUploadProvider(Constants.MEDIA_PATH);
var mod = "PP";
var newFileName = mod + "_" + doc;
await Request.Content.ReadAsMultipartAsync(multiFormDataStreamProvider);
try
{
await FileHelper.Upload(multiFormDataStreamProvider, mod, newFileName);
db.SaveChanges();
return Content(HttpStatusCode.Created, "Data was save");
}
catch (Exception ex)
{
return Content(HttpStatusCode.BadRequest, ex);
}
}
}
catch (Exception ex)
{
return Content(HttpStatusCode.BadRequest, ex);
}
}
进入此部分时出现错误 等待Request.Content.ReadAsMultipartAsync(multiFormDataStreamProvider);
这是错误
ioexception:mime多部分流的意外结束。哑剧 邮件与邮递员的测试不完整
有人知道为什么吗?并帮助我上传文件和数据模型吗? 非常感谢您的帮助
答案 0 :(得分:0)
好的,我找到了答案。为了保存文件和表格数据,我不解析模型。我只是使用表单数据从邮递发送数据,其值为Json数据。因此,我从ReadAsMultipartAsync读取了请求并获取了Json数据,然后反序列化了json。之后,我们可以保存数据。
这就是我从邮递区发送数据的方式 Postmant
这是代码
public async Task<IHttpActionResult> PostArPumPd()
{
try
{
var multiFormDataStreamProvider = new MultiFileUploadProvider(Constants.MEDIA_PATH);
var readToProvider = await Request.Content.ReadAsMultipartAsync(multiFormDataStreamProvider);
// Get Json Data and Deserialize it
var json = await readToProvider.Contents[0].ReadAsStringAsync();
tx_arPumPd a = JsonConvert.DeserializeObject<tx_arPumPd>(json);
// Set mod and file name for FileHelper classl
var mod = "PP";
var newFileName = mod + "_" + doc ;
tx_arPumPd arpumpds = new tx_arPumPd()
{
doc_no = doc,
doc_date = DateTime.Now,
descs = a.descs,
currency_code = a.currency_code,
amount = a.amount,
employee_code = a.employee_code,
head_code = a.head_code,
company_code = a.company_code,
created_by = a.emp_code,
created_date = DateTime.Now
};
db.tx_arPumPd.Add(arpumpds);
var dtl = a.tx_arPumPdDtl;
foreach (var item in dtl)
{
item.doc_no = doc;
item.bg_is_ok = true;
item.bg_approved = true;
item.bg_app_date = DateTime.Now;
item.created_by = a.emp_Code;
item.created_date = DateTime.Now;
db.tx_arPumPdDtl.Add(item);
}
try
{
await FileHelper.Upload(multiFormDataStreamProvider, mod, newFileName);
db.SaveChanges();
return Content(HttpStatusCode.Created, "Data was save");
}
catch (Exception ex)
{
return Content(HttpStatusCode.BadRequest, ex);
}
}
catch (Exception ex)
{
return Content(HttpStatusCode.BadRequest, ex);
}
}
如果有人有更好的方法可以做到这一点,我仍然很高兴了解它。 谢谢。