Question

以下是WPF应用程序的代码段，其中我正在使用ListView控件和自定义ListView控件，但是在UI中，自定义ListView控件显示了类名，而List View控件则显示了实际数据[即Class1的Text1属性值]。我知道通过覆盖Class1的ToString（）可以使我的自定义ListView显示实际数据，但是我不想覆盖ToString（）。因此，有没有办法将自定义ListView的模板更改为类似于ListView控件的工作方式？

MainWindow.xaml：

class Animal{
   int age;
   String type;

   public Animal(int age, String type){
      this.age = age;
      this.type = type;
   }
}
public class MainCls{
   public static void main(String[] args){
       Animal[] arr = {new Animal(2, "Her"), new Animal(3,"Car")};
       Arrays.sort(arr);
   }
}

MainWindow.xaml.cs

<Window
                x:Class="Swip.MainWindow"
                xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
                xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
                xmlns:controls="clr-namespace:Custom.Controls;assembly=Custom.Controls"
                xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
                xmlns:local="clr-namespace:Swip"
                xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
                Title="MainWindow"
                Width="525"
                Height="350"
                mc:Ignorable="d">

                <Grid d:DataContext="{d:DesignInstance d:Type=local:MainWindowModel}">
                    <Grid.ColumnDefinitions>
                        <ColumnDefinition Width="5*" />
                        <ColumnDefinition Width="5*" />
                    </Grid.ColumnDefinitions>

                    <controls:SwipableListView Grid.Column="0" ItemsSource="{Binding Items, Mode=OneWay}">
                        <controls:SwipableListView.View>
                            <GridView>
                                <GridView.Columns>
                                    <GridViewColumn DisplayMemberBinding="{Binding Path=Text1}" Header="11" />
                                </GridView.Columns>
                            </GridView>
                        </controls:SwipableListView.View>
                    </controls:SwipableListView>

                    <ListView Grid.Column="1" ItemsSource="{Binding Items, Mode=OneWay}">
                        <ListView.View>
                            <GridView>
                                <GridView.Columns>
                                    <GridViewColumn DisplayMemberBinding="{Binding Path=Text1}" Header="11" />
                                </GridView.Columns>
                            </GridView>
                        </ListView.View>
                    </ListView>             
                </Grid>             
            </Window>

ViewModel

  /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        public MainWindow()
        {
            InitializeComponent();
            DataContext=new MainWindowModel();
        }
    }

自定义控件模板

 public class MainWindowModel
                {
                    public MainWindowModel()
                    {
                        this.Items = new ObservableCollection<Class1>
                        {
                            new Class1(1),
                            new Class1(2),
                            new Class1(3),
                        };

                        this.DeleteCommand = new RoutedCommand("Delete", typeof(MainWindowModel));
                    }

                    public ObservableCollection<Class1> Items { get; private set; }

                    public ICommand DeleteCommand { get; set; }
                }

Answer 1

Clemens建议-通过将ContentPresenter更改为GridViewRowPresenter，可以解决此问题。请参阅：ListView Styles and Templates

自定义ListViewItem控件显示类名，而常规ListView控件则显示实际数据

1 个答案: